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3 years ago

7

Jason will use a 1/3 gallon pitcher to fill an empty three-quarter gallon water jug. How much water will he need in order to com

pletely fill the water jug

2 answers:

kolbaska11 [484]3 years ago

6 0

He'll need 3/4 gallons of water

Inessa05 [86]3 years ago

6 0

Answer:

half of a full pitcher

Step-by-step explanation:

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Zoey walked from school to the grocery store, and then to her house. The diagram shows the top view of the three locations and s

pashok25 [27]

Answer:

56

Step-by-step explanation:

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3 years ago

Which expressions are equivalent to 8.9 x + 6.2 + 8.7? Check all that apply. 9 x + 6 + 9 8.9 + 6.2 + 8.7 x 8.9 x + 8.7 + 6.2 8.7

Leokris [45]

Answer:

8.9x + 6.2 + 8.7 equals..

8.9x + 8.7 + 6.2

8.7 + 8.9x + 6.2

6.2 + 8.7 + 8.9x

Step-by-step explanation:

Addition is a property that can be done in any order. Multiplication can not be moved around. The variable x is tied to the 8.9 with multiplication, so it must always be attached to it. The other numbers can be moved around because it is addition.

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3 years ago

Find all values of c in the open interval (a, b) such that f'(c)=(f(b)-f(a))/(b-a)

timama [110]

<h3>Answer: c = 7/4</h3>

================================================

Work Shown:

Compute the function value at the endpoints

$f(x) = \sqrt{4-x}\\\\f(-5) = \sqrt{4-(-5)} = 3\\\\f(4) = \sqrt{4-4} = 0\\\\$

With a = -5 and b = 4, we have

$f'(c) = \frac{f(b)-f(a)}{b-a}\\\\f'(c) = \frac{f(4)-f(-5)}{4-(-5)}\\\\f'(c) = \frac{0-3}{9}\\\\f'(c) = -\frac{1}{3}\\\\$

So,

$f(x) = \sqrt{4-x}\\\\f'(x) = -\frac{1}{2\sqrt{4-x}}\\\\f'(c) = -\frac{1}{3}\\\\-\frac{1}{2\sqrt{4-c}} = -\frac{1}{3}\\\\$

Use algebra to solve for c

$-\frac{1}{2\sqrt{4-c}} = -\frac{1}{3}\\\\\frac{1}{2\sqrt{4-c}} = \frac{1}{3}\\\\3 = 2\sqrt{4-c}\\\\2\sqrt{4-c} = 3\\\\\sqrt{4-c} = \frac{3}{2}\\\\4-c = \frac{9}{4}\\\\c = 4-\frac{9}{4}\\\\c = \frac{16-9}{4}\\\\c = \frac{7}{4}\\\\$

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3 years ago

MARKING BRAINLIEST ....loll

Ganezh [65]

A. 5/12
250/600=5/12

8 0

3 years ago

Difference between 205 70 15 and 205 65 15

bogdanovich [222]

The answer would be 500

4 0

3 years ago