Answer:
1) Attached please find the graph of the equation 1/2·y + 2 = 0
2) The values of the y-coordinates for the points are the same, while the values of the x-coordinate of the points increases as we move from left to right
3) The result of substituting the x values of two points on the line in the equation 1/2·y + 2 = 0, gives y = -4, which proves that they are solutions of the linear equation
Step-by-step explanation:
1) The given equation is 1/2·y + 2 = 0
Therefore, the given equation in slope and intercept form, y = m·x + c, can be presented as follows;
1/2·y + 2 = 0
1/2·y = 0 - 2 = -2
y = -2 × 2 = -4
y = -4
Therefore, by comparing the above equation with the equation for a straight line, y = m·x + c, we have;
m = 0, c = -4
Therefore, the graph is an horizontal line with y-intercept at (0, -4)
2) The relationship of the solutions (points) on of the line have with each other are;
a) The values of the y-coordinates for the points are the same, while the values of the x-coordinate of the points increases as we move from left to right
3) Two points on the line are the points (3, -4) and (33, -4)
With the slope = 0, the linear equation is given as follows;
y = 0·x - 4
For the point (3, -4) we have;
y = 0×3 - 4 = -4
y = -4
For the point (33, -4) we have;
y = 0×33 - 4 = -4
y = -4
Therefore, the two points are solutions of the linear equation 1/2·y + 2 = 0, where y = -4.
