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Svetradugi [14.3K]
3 years ago
7

How would you prove lines parallel using this equation?

Mathematics
1 answer:
borishaifa [10]3 years ago
8 0
If  5 = 6 , than 4 =7

so, line L // m
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Find the midpoint of the line segment whose endpoints are (-2, 5) and (4, -9).Find the midpoint of the line segment whose endpoi
jek_recluse [69]

Answer:

The midpoint is (1,-2)

Step-by-step explanation:

we know that

The formula to calculate the midpoint between two points is equal to

M(\frac{x1+x2}{2},\frac{y1+y2}{2})

we have

(x1,y1)=(-2,5)

(x2,y2)=(4,-9)

substitute

M(\frac{-2+4}{2},\frac{5-9}{2})

M(1,-2)

8 0
2 years ago
What is this in standard form ? Please !
Alexxandr [17]

Answer:

-6x + -36 = y + 4

-6x -y = 4 + 36

A. 6x + y = - 40

5 0
3 years ago
Read 2 more answers
Solve the equation and check the solution.
weqwewe [10]

Answer:

C

Step-by-step explanation:

You can write the equation like this:

A - 2.5 = 1.5

If you reverse the equation, it looks like this:

1.5 - 2.5 = A

1.5 - 2.5 = 4

A = 4

3 0
2 years ago
Read 2 more answers
Please simplify, 50 points.
olga55 [171]

Answer:

The trigonometric equation  (sin Θ − cos Θ)^2 − (sin Θ + cos Θ)^3 can be simplified by:Using x for Θ: (sinx - cosx)^2 - (sinx + cosx)^2 = (sin^2 x - 2sinxcosx + cos^2 x) - (sin^2 x + 2sinxcosx + cos^2 x) = - 2 sinx cosx - 2 sinx cosx = - 4 sinx cosx = - 2sin(2x)

Step-by-step explanation:

4 0
3 years ago
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Please answer quickly<br>expand and simplify: 4(5x-3y) (x-4y) -(3x-4y)(2x+3y)​
Gekata [30.6K]

Answer: 14x^2-93xy+60y^2 Hope that helps!

Step-by-step explanation:

1. Expand by distributing terms

(20x-12y)(x-4y)-(3x-4y)(2x+3y)

2. Use the Foil method:(a+b)(c+d)= ac+ad+bc+bd

20x^2-80xy-12yx+48y^2-(3x-4y)(2x+3y)

3. Use the Foil method : (a+b)(c+d)= ac+ad+bc+bd

20x^2-80xy-12yx+48y^2-(6x^2+9xy-8yx-12y^2)

4. Remove parentheses 20x^2-80xy-12yx+48y^2-6x^2-9xy+ 8yx+12y^2

5. Collect like terms (20x^2-6x^2)+(-80xy-12xy-9xy+8xy)+(48y^2+12y^2)

6. Simplify.

And your answer would be 14x^2-93xy+60y^2

5 0
2 years ago
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