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Tpy6a [65]
3 years ago
9

Answer problems. Really need help

Mathematics
1 answer:
pentagon [3]3 years ago
6 0
1. x^2+6x+5
(x+5)(x+1)
x=-5 and -1
2 and 4 require the quadratic formula which is the picture above. To know what numbers to plug in, you have to know that quadratic equation is as it follows
ax^2+bx+c

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Mademuasel [1]
Answer A and Answer D along with the ones you picked beforehand
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4 1/3 - 1 2/3 how to solve this please
8_murik_8 [283]

Answer:

2\frac{2}{3}

Step-by-step explanation:

1) Convert 4\frac{1}{3} to improper fraction. Use this rule: a\frac{b}{c} =\frac{ac+b}{c}.

\frac{4\times3+1}{3} -1\frac{2}{3}

2) Simplify 4 * 3 to 12.

\frac{12+1}{3}

3) Simplify 12 + 1 to 13.

\frac{13}{3} -1\frac{2}{3}

4) Convert 1\frac{2}{3}   to improper fraction. Use this rule: a\frac{b}{c} =\frac{ac+b}{c}.

\frac{13}{3} -\frac{1\times3+2}{3}

5) Simplify 1 * 3 to 3.

\frac{13}{3} -\frac{3+2}{3}

6) Simplify 3 + 2 to 5.

\frac{13}{3} -\frac{5}{3}

7) Join the denominators.

\frac{13-5}{3}

8) Simplify.

\frac{8}{3}

9) Convert to mixed fraction.

2\frac{2}{3}

(Decimal Form: 2.666667)

Thank you,
Eddie

3 0
2 years ago
Solve for x<br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B11%7D%7Bx%2B5%7D" id="TexFormula1" title="\frac{11}{x+5}" alt="\frac
Vika [28.1K]
The answer is X = -4/3
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2 years ago
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Yael used to have a square garage with 254 ft2 of floor space. She recently built an addition to it. The garage is still a​ squa
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120

Step-by-step explanation:

5 0
3 years ago
You are graphing Square ABCDABCDA, B, C, D in the coordinate plane. The following are three of the vertices of the square: A(4,
Kitty [74]

Answer:

D(4,-3)

Step-by-step explanation:

Given three of the vertices of the square: A(4, -7), B(8, -7),C(8, -3)

Let the coordinate of the fourth vertex be D(x,y).

We know that diagonals of a square are perpendicular bisector. So, the midpoint of both diagonals is the same.

The diagonals are BD and AC

Midpoint of BD = Midpoint of AC

\left(\dfrac{8+x}{2},\dfrac{-7+y}{2}\right) =\left(\dfrac{4+8}{2},\dfrac{-7+(-3)}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(\dfrac{12}{2},\dfrac{-10}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(6,-5\right)\\$Therefore$:\\\dfrac{8+x}{2}=6\\8+x=12\\x=12-8\\x=4\\$Similarly$\\\dfrac{y-7}{2}=-5\\y-7=-5*2\\y-7=-10\\y=-10+7=-3

The coordinates of the fourth vertex is D(4,-3)

3 0
3 years ago
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