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Tpy6a [65]
3 years ago
9

Answer problems. Really need help

Mathematics
1 answer:
pentagon [3]3 years ago
6 0
1. x^2+6x+5
(x+5)(x+1)
x=-5 and -1
2 and 4 require the quadratic formula which is the picture above. To know what numbers to plug in, you have to know that quadratic equation is as it follows
ax^2+bx+c

You might be interested in
A=2x+6xz <br> a=2x+6xz<br> for x
Dennis_Churaev [7]
So I guess we are solving for x here :)
So here is my work...
a=2x+6xz
Basically I think it would be
a=6xz+2x

WAIT WAIT NO I'M WRONG FORGIVE ME!

It's  x=a/2(1+3z)
5 0
3 years ago
Read 2 more answers
Shay and Nadine solve this problem in two different ways. You have $25 in your bank account. You make $7 per hour babysitting. H
myrzilka [38]
The answer to this problem is 25
8 0
3 years ago
Read 2 more answers
Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive
NeX [460]

Answer:

(a) 0.343

(b) 0.657

(c) 0.189

(d) 0.216

(e) 0.353

Step-by-step explanation:

Let P(a vehicle passing the test) = p

                        p = \frac{70}{100} = 0.7  

Let P(a vehicle not passing the test) = q

                         q = 1 - p

                         q = 1 - 0.7 = 0.3

(a) P(all of the next three vehicles inspected pass) = P(ppp)

                           = 0.7 × 0.7 × 0.7

                           = 0.343

(b) P(at least one of the next three inspected fails) = P(qpp or qqp or pqp or pqq or ppq or qpq or qqq)

      = (0.3 × 0.7 × 0.7) + (0.3 × 0.3 × 0.7) + (0.7 × 0.3 × 0.7) + (0.7 × 0.3 × 0.3) + (0.7 × 0.7 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.3)

      = 0.147 + 0.063 + 0.147 + 0.063 + 0.147 + 0.063 + 0.027

      = 0.657

(c) P(exactly one of the next three inspected passes) = P(pqq or qpq or qqp)

                 =  (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

                 = 0.063 + 0.063 + 0.063

                 = 0.189

(d) P(at most one of the next three vehicles inspected passes) = P(pqq or qpq or qqp or qqq)

                 =  (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7) + (0.3 × 0.3 × 0.3)

                 = 0.063 + 0.063 + 0.063 + 0.027

                 = 0.216

(e) Given that at least one of the next 3 vehicles passes inspection, what is the probability that all 3 pass (a conditional probability)?

P(at least one of the next three vehicles inspected passes) = P(ppp or ppq or pqp or qpp or pqq or qpq or qqp)

=  (0.7 × 0.7 × 0.7) + (0.7 × 0.7 × 0.3) + (0.7 × 0.3 × 0.7) + (0.3 × 0.7 × 0.7) + (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

= 0.343 + 0.147 + 0.147 + 0.147 + 0.063 + 0.063 + 0.063

                  = 0.973  

With the condition that at least one of the next 3 vehicles passes inspection, the probability that all 3 pass is,

                         = \frac{P(all\ of\ the\ next\ three\ vehicles\ inspected\ pass)}{P(at\ least\ one\ of\ the\ next\ three\ vehicles\ inspected\ passes)}

                         = \frac{0.343}{0.973}

                         = 0.353

3 0
3 years ago
Read 2 more answers
Can someone help me with this
Art [367]

Ans57 , 58 , 59

Step-by-step explanation:

5 0
2 years ago
What set of reflections would carry hexagon ABCDEF onto itself?
Marianna [84]

When a set of reflections that carry a shape onto itself, it means that the final position of the shape will be the same as its original location

Reflections <em>(a) y=x, x-axis, y=x, y-axis </em>would carry the hexagon onto itself

First; we test the given options, until we get the true option

<u>(a) y=x, x-axis, y=x, y-axis</u>

The rule of reflection y =x is:

(x,y) \to (y,x)

The rule of reflection across the x-axis is:

(x,y) \to (x,-y)

So, we have:

(y,x) \to (y,-x)

The rule of reflection y =x is:

(x,y) \to (y,x)

So, we have:

(y,-x) \to (-x,y)

Lastly, the reflection across the y-axis is:

(x,y) \to (-x,y)

So, we have:

(-x,y) \to (x,y)

So, the overall transformation is:

(x,y) \to (x,y)

Notice that, the original and final coordinates are the same.

This means that:

Reflections <em>(a) y=x, x-axis, y=x, y-axis </em>would carry the hexagon onto itself

Read more about reflections at:

brainly.com/question/938117

4 0
2 years ago
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