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Gennadij [26K]
3 years ago
8

A variable that cannot be measured in terms of how much or how many but instead is assigned values to represent categories is ca

lled a(n) _____.
Mathematics
2 answers:
Anastaziya [24]3 years ago
3 0

Answer: a qualitative variable

Step-by-step explanation :

A qualitative variable, also called a categorical variable, are variables that are not numerical.

It describes data that fits into categories. For example: Eye colors (variables include: blue, green, brown, hazel)

serg [7]3 years ago
3 0

Answer:

a. a qualitative variable

Step-by-step explanation:

A variable that cannot be measured in terms of how much or how many but instead is assigned values to represent categories is called a(n) _____.

Variables are containers, they contain values. examples of variables are the following

. a qualitative variable

b. a constant variable

c. a category variable

d. an interaction

qualitative variables are variables that have no numerical value attached to them. They are variables that can't be measured.

e.g colour of the eyes(blue, brown etc)

therefore, qualitative variables cannot be measured in terms of how much or how many.

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Please help no links
Nina [5.8K]

Answer:

x=5 y=-6

Step-by-step explanation:

3x+y=9 ------eqn1

y=4-2x -------eqn2

using substitution

put y=4-2x into eqn1

3x+4-2x=9

x=5

put x=5 into eqn2

y=4-2(5)

y=4-10

y=-6

8 0
3 years ago
What is the answer to this equation: 40+40-20x0+3+125=
MrRa [10]

Answer:

208

Step-by-step explanation:

20 × 0 = 0

40 + 40 = 80

125 + 3 = 128

3 0
3 years ago
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What is the value of the expression below?
garri49 [273]

Answer:

9

Step-by-step explanation:

15 - 7 \times 2 + 2^3 =

Use the correct order of operations, PEMDAS.

= 15 - 14 + 8

= 1 + 8

= 9

8 0
3 years ago
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If cos() = − 2 3 and is in Quadrant III, find tan() cot() + csc(). Incorrect: Your answer is incorrect.
nydimaria [60]

Answer:

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}

Step-by-step explanation:

Given

\cos(\theta) = -\frac{2}{3}

\theta \to Quadrant III

Required

Determine \tan(\theta) \cdot \cot(\theta) + \csc(\theta)

We have:

\cos(\theta) = -\frac{2}{3}

We know that:

\sin^2(\theta) + \cos^2(\theta) = 1

This gives:

\sin^2(\theta) + (-\frac{2}{3})^2 = 1

\sin^2(\theta) + (\frac{4}{9}) = 1

Collect like terms

\sin^2(\theta)  = 1 - \frac{4}{9}

Take LCM and solve

\sin^2(\theta)  = \frac{9 -4}{9}

\sin^2(\theta)  = \frac{5}{9}

Take the square roots of both sides

\sin(\theta)  = \±\frac{\sqrt 5}{3}

Sin is negative in quadrant III. So:

\sin(\theta)  = -\frac{\sqrt 5}{3}

Calculate \csc(\theta)

\csc(\theta) = \frac{1}{\sin(\theta)}

We have: \sin(\theta)  = -\frac{\sqrt 5}{3}

So:

\csc(\theta) = \frac{1}{-\frac{\sqrt 5}{3}}

\csc(\theta) = \frac{-3}{\sqrt 5}

Rationalize

\csc(\theta) = \frac{-3}{\sqrt 5}*\frac{\sqrt 5}{\sqrt 5}

\csc(\theta) = \frac{-3\sqrt 5}{5}

So, we have:

\tan(\theta) \cdot \cot(\theta) + \csc(\theta)

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \tan(\theta) \cdot \frac{1}{\tan(\theta)} + \csc(\theta)

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 + \csc(\theta)

Substitute: \csc(\theta) = \frac{-3\sqrt 5}{5}

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 -\frac{3\sqrt 5}{5}

Take LCM

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}

6 0
3 years ago
What is |–16|? <br><br> A.<br> 16<br><br> B.<br> 4<br><br> C.<br> –4<br><br> D.<br> –16
Aleksandr-060686 [28]
I hope this helps you


(-)×(-)=+


-(-16)


+16
3 0
3 years ago
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