To solve this problem, we need to know the formula for the nth term of an arithmetic sequence. The formula is

= t₁ + (n-1)d, with

being the nth term, t₁ being the first term, and d being the distance between terms. Now we can substitute values to figure out what

is. When substituting, the equation becomes:

= 12 + 29(-6)

= -162
That means that the 30th term in this arithmetic sequence is
-162.
Answer:

Step-by-step explanation:
move the terms with
to the left side of the equation:
add 3x to both sides

add 3x and 3x

move all term not containing
to the right side:
add 1 to both sides of the equation


divide each term by 6


simplify the fraction

Circumference=2pi*r
20.7=2pi*r
r=3.296 or 3.3
A=pir^2
a=34.1946 or about 34.19
Solution:XOR: X+Y= XY’ + X’YDual of XOR:= (X +Y’)+(X’+Y)= XX’+XY +X’Y’ +YY’= XY + X’Y’ Complement of XOR (XNOR)= (X+Y)’= (XY’ + X’Y)’=(X’+Y)+(X +Y’)= XX’+ XY + X’Y’+YY’= XY + X’Y’
HOPE IT HELPS