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AleksandrR [38]
2 years ago
9

Justin earned $50 mowing yards and $19 washing cars. He wants to divide his money into 3 equal accounts.How much will he put in

each account? Complete the explanation.
Mathematics
1 answer:
ivanzaharov [21]2 years ago
8 0

Answer:

$23

Step-by-step explanation:

50 + 19=69\\69/3=23\\Or -$23 in each account

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If he ate 6/8 of the pizza, that means 2/8 is left.
2/8 simplify it, by dividing it by 2 and your answer is...
IT'S 1/4
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13 is 6 1/2% of what number?
mylen [45]

Answer:

200

Step-by-step explanation:

3 0
1 year ago
Consider a uniform distribution from aequals4 to bequals29. ​(a) Find the probability that x lies between 7 and 27. ​(b) Find th
weeeeeb [17]

Answer:

a) 80% probability that x lies between 7 and 27.

b) 28% probability that x lies between 6 and 13.

c) 44% probability that x lies between 9 and 20.

d) 28% probability that x lies between 11 and 18.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value x between c and d, in which d is larger than c, is given by the following formula.

P(c \leq x \leq d) = \frac{d - c}{b - a}

Uniform distribution from a = 4 to b = 29

(a) Find the probability that x lies between 7 and 27.

So c = 7, d = 27

P(7 \leq x \leq 27) = \frac{27 - 7}{29 - 4} = 0.8

80% probability that x lies between 7 and 27.

​(b) Find the probability that x lies between 6 and 13. ​

So c = 6, d = 13

P(6 \leq x \leq 13) = \frac{13 - 6}{29 - 4} = 0.28

28% probability that x lies between 6 and 13.

(c) Find the probability that x lies between 9 and 20.

​So c = 9, d = 20

P(9 \leq x \leq 20) = \frac{20 - 9}{29 - 4} = 0.44

44% probability that x lies between 9 and 20.

(d) Find the probability that x lies between 11 and 18.

So c = 11, d = 18

P(11 \leq x \leq 18) = \frac{18 - 11}{29 - 4} = 0.28

28% probability that x lies between 11 and 18.

3 0
3 years ago
There are 34 people going on a field trip. if each car holds 4 people. how many cars will we need?
ss7ja [257]

Answer:

9 cars

Step-by-step explanation:

A car holds 4 people

For 34 people :

34 ÷ 4 = 8 1/2

We canmot put 8 1/2 cars so it's 9. There will just be 2 extra seats.

4 0
3 years ago
WILL GIVE BRAINIEST IF DONE IN 10 MINUTES!!!!!
Mama L [17]

Answer:

\sin(\theta)=-12/13\text{ and } \csc(\theta)=-13/12\\\cos(\theta)=-5/13\text{ and } \sec(\theta)=-13/5\\\tan(\theta)=12/5\text{ and } \cot(\theta)=5/12

Step-by-step explanation:

So we know that:

\sin(\theta)=-12/13\text{ and } \sec(\theta)

This tells us that our angle θ is in Quadrant III. This is because, recall ASTC. In QI, everything is positive. This is not the case here since sine and secant are both negative.

In QII, <em>only</em> sine is positive. Since sine is negative, θ can't be in QII.

In QIII, <em>only</em> tangent (and cotangent) is positive. All other are negative. So, θ is in QIII.

And just to check, in QIV, <em>only</em> cosine (and secant) is positive. Since we are told that secant is less than 0 (in other words, negative), θ can't be in QIV.

Now that we know that θ is in QIII, we know that sine and cosecant is negative; cosine and secant is negative; and tangent and cotangent is positive.

Now, let's find the ratios. Remember what sine tells us. Sine gives us the ratio of the <em>opposite</em> side to the <em>hypotenuse</em>. With this information, let's find the adjacent side:

So, the opposite is 12 (ignore the negative for now) and the hypotenuse is 13. Therefore, we can use the Pythagorean Theorem:

a^2+b^2=c^2

Substitute 12 for a and 13 for c:

12^2+b^2=c^2

Now, solve for b to find the adjacent side. Square the values:

144+b^2=169

Subtract 144 from both sides:

b^2=25

Square root:

b=\pm 5

We can ignore the negative and just take the positive. While the answer is technically -5, we don't need to do that. So, our adjacent side is 5.

Therefore, with respect to angle θ, our opposite is 12, our adjacent is 5, and our hypotenuse is 13. With this, we can compute the other trig ratios. Let's start with the 3 main ones:

Sine:

\sin(\theta)

As given, this is -12/13. So:

\sin(\theta)=-12/13

Cosine:

\cos(\theta)=adj/hyp

Substitute 5 for the adjacent and 13 for the hypotenuse. So:

\cos(\theta)=5/13

And since our angle is in QIII, we add a negative:

\cos(\theta)=-5/13

Tangent:

\tan(\theta)=opp/adj

Substitute 12 for opposite and 5 for adjacent. So:

\tan(\theta)=12/5

And since our angle is in QIII, tangent stays positive.

To find the other three, simply flip the previous fractions:

\csc(\theta)=-13/12\\\sec(\theta)=-13/5\\\cot(\theta)=5/12

5 0
3 years ago
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