Answer:
20
Step-by-step explanation:
use PEMDAS.
do 5 x 3, the multiply that by 16/2.
you would get 120.
then divide by 6
1. You have that:
- The<span> lengths of the bases are (6x-1) units and 3 units.
- The midsegment has a length of (5x-3) units.
2. To solve this exercise, you must apply the formula for calculate the length of the midsegment of a trapezoid, which is shown below:
Midsegment=Base1+Base2/2
As you can see, the midsegment is half the sum of the bases of the trapezoid.
3. When you substitute the values, you obtain:
(5x-3)=[(6x-1)+3]/2
4. Now, you can solve the problem by clearing the "x":
</span>
(5x-3)=[(6x-1)+3]/2
2(5x-3)=6x-1+3
10x-6=6x+2
10x-6x=2+6
4x=8
x=8/4
x=2
Answer:
DG = 30
Step-by-step explanation:
Given:
DH = 6
DE = 4
EF = 16
Required:
DG
Solution:
DG = DH + HG
DG = 6 + HG
Let's find HG
Given that HE is parallel to the third side of ∆DGF, based on the side-splitter theorem, the other two sides of ∆DGF are divided proportionally.
Therefore,
DH/HG = DE/EF
6/HG = 4/16
Cross multiply
HG*4 = 16*6
HG = 96/4
HG = 24
✔️DG = 6 + HG
DG = 6 + 24
DG = 30
