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inna [77]
3 years ago
15

Patrick starts hiking at an elevation of -418 feet. He ascends to an elevation of 387 feet and then descends to an elevation 94

feet higher than where he began. He descends 132 feet. What is the elevation of where he stops hiking?. Single line text.

Mathematics
1 answer:
const2013 [10]3 years ago
6 0
-456 Feet is the answer
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Ivanna jogged for 35 minutes.
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Ivanna started jogging at 7:20
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Lola takes the train from Paris to Nice. The distance between the two cities is about 900,000 meters. If the train travels at a
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Nice??? there is a city called nice? anyways, your answer is 5000. hope this helps :)
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A cable pole casts a shadow that is 12 feet long . If a 6ft tall man casts a shadow thats is 4 feet long how tall is the cable p
shepuryov [24]

Answer:

18ft

Step-by-step explanation:

6ft -> 4ft shadow

6 = 4m

m = 6/4

y = 12m

y = 12(6/4)

y = 18ft

4 0
3 years ago
OLEASE HELP I BEGGG YOU PLEASEEEEE
rodikova [14]

Answer:

I think b because it goes from most to least sorry if u can't understand

8 0
3 years ago
Which two values of x are roots of the polynomial below?<br> x2-11x + 15
Alex787 [66]

The two values of roots of the polynomial x^{2}-11 x+15 are \frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}

<u>Solution:</u>

Given, polynomial expression is x^{2}-11 x+15

We have to find the roots of the given expression.

In order to find roots, now let us use quadratic formula.

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Given that x^{2}-11 x+15

Here a = 1, b = -11 and c = 15

On substituting the values we get,

x=\frac{-(-11) \pm \sqrt{(-11)^{2}-4 \times 1 \times 15}}{2 \times 1}

\begin{array}{l}{x=\frac{11 \pm \sqrt{121-60}}{2}} \\\\ {x=\frac{11 \pm \sqrt{61}}{2}} \\\\ {x=\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}}\end{array}

Hence, the roots of given polynomial are \frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}

6 0
3 years ago
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