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Delicious77 [7]
3 years ago
15

Deshaun and his wife are each starting a saving plan. Deshaun will initially set aside $750 and then add $135 every month to the

savings. The amount A (in dollars) saved this way is given by the function A=750+135N , where N is the number of months he has been saving. His wife will not set an initial amount aside but will add $485 to the savings every month. The amount B (in dollars) saved using this plan is given by the function B=485N. Let T be total amount (in dollars) saved using both plans combined. Write an equation relating T to N .
Simplify your answer as much as possible.\
Mathematics
2 answers:
lara [203]3 years ago
5 0

Answer:

The equation that relates T to N is T=750 + 620*N

Step-by-step explanation:

On the one hand, you know that what Deshaun saved is:

A = 750 + 135 * N

where N is the number of months you have been saving

On the other hand, what his wife saves is: B = 485 * N

The total amount saved using both plans combined implies the sum of what was saved by Deshaun and his wife. So:

T=A + B

Then:

T=750 + 135*N + 485*N

T=750 + 620*N

<u><em>The equation that relates T to N is T=750 + 620*N</em></u>

Bumek [7]3 years ago
3 0
If A=750+135N; and B=485N, then A+B=
750+135N+485N=750+620N
T=620N+750
☺☺☺☺
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Harold has 4 classes each morning. Each class is 1 hour long, and there are 10 minutes between classes. The first class is at 8
Viktor [21]

The fourth class ends at 12:30 pm

<em><u>Solution:</u></em>

Given that Harold has 4 classes each morning

Each class is 1 hour long, and there are 10 minutes between classes

The first class is at 8 A.M

<em><u>To find: Time at which fourth class ends</u></em>

Since each is 1 hour long and 10 minutes gap between classes

First class = 8 A.M to 9 A.M

Second class = 9:10 A.M to 10 : 10 AM

Third class = 10 : 20 AM to 11 : 20 AM

Fourth class = 11 : 30 AM to 12 : 30 PM

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3 years ago
A) Find the distance of line segment PR. Round answer to the nearest tenth. B) Find the distance around the park (perimeter).
juin [17]

Answer:

A. PR = 80.6 yd

B. Perimeter = 190.6 yd

Step-by-step explanation:

A. Distance between P(10, 50) and R(80, 10):

PR = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

PR = \sqrt{(80 - 10)^2 + (10 - 50)^2}

PR = \sqrt{(70)^2 + (-40)^2}

PR = \sqrt{4,900 + 1,600}

PR = \sqrt{6,500}

PR = 80.6 yd (nearest tenth)

B. Distance around the park = Perimeter = PR + PQ + QR

PR = 80.6 yd

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QR = |80 - 10| = 70 yd

Perimeter = 80.6 + 40 + 70

Perimeter = 190.6 yd

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3 years ago
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Answer:

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A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num
yKpoI14uk [10]

Answer: hypotenuse = c^{2} + b^{2}

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side (s_{1},s_{2}) of the right triangle, .i.e.:

h^{2} = s_{1}^{2} + s_{2}^{2}

In this question:

s_{1} = c^{2}-b^{2}

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Substituing and taking square root to find hypotenuse:

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