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3 years ago

Please solve ASAP, 3k+16=9+6x? and show ur work please?

Mathematics

1 answer:

denis23 [38]3 years ago

7 0

Answer:

$\Large \boxed{k=2x + \frac{-7}{3}} \\ \\ \\ \Large \boxed{x=\frac{1}{2} k+\frac{7}{6}}$

Step-by-step explanation:

Solving for k:

$\sf 3k+16=9+6x$

Subtracting 16 from both sides.

$\sf 3k=6x-7$

Dividing both sides by 3.

$\displaystyle \sf k=2x + \frac{-7}{3}$

Solving for x:

Flipping the original equation.

$\sf 6x+9=3k+16$

Subtracting 9 from both sides.

$\sf 6x=3k+7$

Dividing both sides by 6.

$\sf \displaystyle x=\frac{1}{2} k+\frac{7}{6}$

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4 years ago

G a frequency distribution has a mean of 200 and a standard deviation of 20. the class limits for one class are 220 up to 240. b

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4 years ago

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3 years ago

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3 years ago

Read 2 more answers

Let k ( x ) = 2 x + 3 and m ( x ) = 3 x 2 + 7 x − 10 . Find the indicated value. M ( k ( − 4 ) ) =

murzikaleks [220]

Answer: $30$

Step-by-step explanation:

Given

$k(x)=2x+3$

$M(x)=3x^2+7x-10$

$M\left(k(x)\right)$ is given by replacing the $x$ by $k(x)$ from the $M(x)$

$\Rightarrow M\left(k(x)\right)=3(2x+3)^2+7(2x+3)-10\\\Rightarrow M\left(k(x)\right)=3(4x^2+9+12x)+14x+21-10\\\Rightarrow M\left(k(x)\right)=12x^2+50x+38$

Now, $M\left(k(-4)\right)$ is

$\Rightarrow M\left(k(-4)\right)=12(-4)^2+50(-4)+38\\\Rightarrow M\left(k(-4)\right)=192-200+38\\\Rightarrow M\left(k(-4)\right)=30$

8 0

3 years ago

Please solve ASAP, 3k+16=9+6x? and show ur work please?​

Please solve ASAP, 3k+16=9+6x? and show ur work please?