HELP YOU WILL GET BRAINLIEST

What’s the answer no work needed Given f (x) = 5x2 and g(x) = 2x + 3, find f(g(-4))

Crazy boy [7]

Answer:

125

Step-by-step explanation:

Given

f(x) = 5x²

g(x) = 2x + 3

Now

g(-4) = 2 * (- 4) + 3

= - 8 + 3

= - 5

Also

f(g(-4)) = f( -5)

= 5 * ( -5)²

= 5 * 25

= 125

4 0

2 years ago

£980 is divided between Caroline, Sarah & Gavyn so that Caroline gets twice as much as Sarah, and Sarah gets three times as

Nitella [24]

Sarah has received £ 294

Solution:

Given that £980 is divided between Caroline, Sarah & Gavyn

Let "c" be the amount received by caroline

Let "s" be the amount received by sarah

Let "g" be the amount received by gavyn

Caroline gets twice as much as Sarah

amount received by caroline = twice as much as Sarah

amount received by caroline = 2(amount received by sarah)

c = 2s ---- eqn 1

Sarah gets three times as much as Gavyn

amount received by sarah = three times as much as Gavyn

amount received by sarah = 3(amount received by gavyn)

s = 3g ------- eqn 2

Given that total amount is 980

c + s + g = 980 --- eqn 3

Let us solve eqn 1, 2, 3 to get values of "c" "s" "g"

From eqn 2,

$g = \frac{s}{3}$ --- eqn 4

Substitute eqn 1 and eqn 4 in eqn 3

$2s + s + \frac{s}{3} = 980\\\\\frac{6s + 3s + s}{3} = 980\\\\6s + 3s + s = 980 \times 3\\\\10s = 2940\\\\s = 294$

Thus sarah has received £ 294

7 0

3 years ago

Un estudiante debe recorrer dos tercios de kilómetro para llegar al colegio, si avanza medio kilómetro en bus y lo demás a pie ¿

Murljashka [212]

Answer:

Al estudiante le falta caminar $\frac{1}{3}$ de kilómetro.

Step-by-step explanation:

Un estudiante debe recorrer dos tercios de kilómetro para llegar al colegio. Dos tercios equivale a la fracción $\frac{2}{3}$ .

El estudiante avanza medio kilómetro en bus. Un medio equivale a la fracción $\frac{1}{2}$ , por lo tanto un medio es la mitad de una cantidad. Para calcular la distancia recorrida en bus se realiza la siguiente multiplicación:

$\frac{1}{2} *\frac{2}{3}$

Resolviendo:

$\frac{1}{2} *\frac{2}{3} =\frac{1*2}{2*3} =\frac{2}{6} =\frac{1}{3}$

Entonces, la distancia recorrida en bus es $\frac{1}{3}$ de kilómetro.

Para calcular la distancia recorrida a pie se calcula la diferencia entre la distancia total a recorrer por el estudiante y la distancia recorrida en bus. Esto es:

$\frac{2}{3} - \frac{1}{3}$

Resolviendo:

$\frac{2}{3} - \frac{1}{3}=\frac{2-1}{3} =\frac{1}{3}$

Al estudiante le falta caminar $\frac{1}{3}$ de kilómetro.

6 0

3 years ago

Can somebody help me with questions 11 and 12 I’ll appreciate it!

Phoenix [80]

11) 88140 divided by 4520 = 19.5 meaning you would need 20 fire extinguishers

5 0

2 years ago

Read 2 more answers

. The mean width of 12 iPads is 5.1 inches. The mean width of 8 Kindles is 4.8 inches. a. What is the total width of the iPads?

UkoKoshka [18]

Answer:

a) 61.2, b) 38.4 and c) 4.98

Step-by-step explanation:

Given:

The mean width of 12 I-Pads is 5.1 inches.

The mean width of 8 Kindles is 4.8 inches.

Question asked:

a. What is the total width of the I-Pads?

b. What is the total width of the Kindles?

c. What is the mean width of the 12 I-Pads and 8 Kindles?

Solution:

As we know:

$Mean =\frac{Sum\ of\ observations}{Number\ of\ observations}\\ \\ Mean\ width =\frac{Sum\ of\ width\ of\ all \ I-pad}{Number \ of\ I-pad}$

$5.1=\frac{Sum\ of\ width\ of\ all\ I-pad}{12} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all\ I-pad}=5.1\times1 2\\ \\ Sum\ of\ width\ of\ all\ I-pad}= 61.2$

a) Thus, the total width of the I-Pads are 61.2 inches.

$Mean\ width =\frac{Sum\ of\ width\ of\ all\ Kindles}{Number \ of\ Kindles}$

$4.8=\frac{Sum\ of\ width\ of\ all\Kindles}{8} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all \ Kindles=4.8\times8\\ \\ Sum\ of\ width\ of \ all\ Kindles}=38.4$

b) Thus, total width of the Kindles are 38.4 inches.

Combined width of both I-pad and Kindles = 61.2 + 38.4 = 99.6 inches

Combined number of observations = 12 + 8 =20

Combined mean of width of the 12 I-Pads and 8 Kindles = Combined width of both I-pad and Kindles $\div$ Combined number of observations

Combined mean of width of the 12 I-Pads and 8 Kindles = $\frac{99.6}{20} =4.98\ inches$

c) Thus, the mean width of the 12 I-Pads and 8 Kindles is 4.98 inches.

5 0

2 years ago