Answer:
95%
Step-by-step explanation:
We have a normal distribution with a mean of 6 students and standard deviation of 26.
To solve this problem, we're going to need the help of a calculator.
P(16<z<120) = 0.9545 ≈ 95.45%
Rounding, we can say that 95% of the students scored between 16 and 120.
t(1) = 1 = 2(1)-9 / 1 - a
1 - a = 2 - 9 = -7
a = 1 + 7
a = 8 answer
(x - 2)(v + 3)
xv + 3x - 2v - 6
= x(v + 3) - 2(v + 3)
Answer: B
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