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alisha [4.7K]
4 years ago
7

4,000 students take an exam and get scores with a mean of 68 and a standard deviation of 26.

Mathematics
1 answer:
salantis [7]4 years ago
3 0

Answer:

95%

Step-by-step explanation:

We have a normal distribution with a mean of 6 students and standard deviation of 26.

To solve this problem, we're going to need the help of a calculator.

P(16<z<120) = 0.9545 ≈ 95.45%

Rounding, we can say that 95% of the students scored between 16 and 120.

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\large\boxed{D.\ y=-\dfrac{1}{2}x+7}

Step-by-step explanation:

\text{Let}\\k:\ A_1x+B_1=C_1\\\\l:\ A_2x+B_2y=C_2\\\\\text{then}\\\\k\ \parallel\ l\iff A_1=A_2\ \wedge\ B_1=B_2\\==========================

\text{We have the equation:}\ 2x+4y=6\\\\\text{Therefore the equation of a parallel line is:}\ 2x+4y=C\\\\\text{Put the coordinates of the given point to the equation and solve for}\ C:\\\\(6,\ 4)\to x=6,\ y=4\\\\C=2(6)+4(4)\\C=12+16\\C=28\\\\\text{The equation in the standard form:}\\\\2x+4y=28

\text{Convert to the slope-intercept form}\ y=mx+b:\\\\2x+4y=28\qquad\text{subtract}\ 2x\ \text{from both sides}\\\\4y=-2x+28\qquad\text{divide both sides by 4}\\\\y=-\dfrac{2}{4}x+\dfrac{28}{4}\\\\y=-\dfrac{1}{2}x+7

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