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qwelly [4]
3 years ago
5

Factor by grouping. xv+ 3x-2v-6

Mathematics
1 answer:
andrey2020 [161]3 years ago
4 0

Answer:

(x - 2)(v + 3)

Step-by-step explanation:

xv + 3x - 2v - 6

= x(v + 3) - 2(v + 3)

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Step-by-step explanation:

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What is (-3)-(-6)×(-9)?
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(-3)-(-6)×(-9)

Simplify your equation to make it look neater.

(-3)+(6)×(-9)

Combine like terms.

(-3+6)×(-9)

Simplify.

(3)×(-9)

Simplify. Remember, a negative times a positive is ALWAYS a negative. 

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3 0
3 years ago
Jamal spent the day making a painting for his friend.At the end he finished 1/2 of the painting . How long would it take to make
ivanzaharov [21]
It would take about 4 days because for one day he can paint half a painting. there are 4 halves in 2 wholes so it would take 4 days

4 0
3 years ago
What the second answer ​
Debora [2.8K]

Answer:

1. y' = 3x² / 4y²

2. y'' = 3x/8y⁵[(4y³ – 3x³)]

Step-by-step explanation:

From the question given above, the following data were obtained:

3x³ – 4y³ = 4

y' =?

y'' =?

1. Determination of y'

To obtain y', we simply defferentiate the expression ones. This can be obtained as follow:

3x³ – 4y³ = 4

Differentiate

9x² – 12y²dy/dx = 0

Rearrange

12y²dy/dx = 9x²

Divide both side by 12y²

dy/dx = 9x² / 12y²

dy/dx = 3x² / 4y²

y' = 3x² / 4y²

2. Determination of y''

To obtain y'', we simply defferentiate above expression i.e y' = 3x² / 4y². This can be obtained as follow:

3x² / 4y²

Let:

u = 3x²

v = 4y²

Find u' and v'

u' = 6x

v' = 8ydy/dx

Applying quotient rule

y'' = [vu' – uv'] / v²

y'' = [4y²(6x) – 3x²(8ydy/dx)] / (4y²)²

y'' = [24xy² – 24x²ydy/dx] / 16y⁴

Recall:

dy/dx = 3x² / 4y²

y'' = [24xy² – 24x²y (3x² / 4y² )] / 16y⁴

y'' = [24xy² – 18x⁴/y] / 16y⁴

y'' = 1/16y⁴[24xy² – 18x⁴/y]

y'' = 1/16y⁴[(24xy³ – 18x⁴)/y]

y'' = 1/16y⁵[(24xy³ – 18x⁴)]

y'' = 6x/16y⁵[(4y³ – 3x³)]

y'' = 3x/8y⁵[(4y³ – 3x³)]

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Answer:

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Step-by-step explanation:

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