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qwelly [4]
2 years ago
5

Factor by grouping. xv+ 3x-2v-6

Mathematics
1 answer:
andrey2020 [161]2 years ago
4 0

Answer:

(x - 2)(v + 3)

Step-by-step explanation:

xv + 3x - 2v - 6

= x(v + 3) - 2(v + 3)

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Select the answer choice that equals the given expression. 8^-3 x 8^-2 x ^5
Alexus [3.1K]

Answer:

B) 1

Step-by-step explanation:

Given:

8^{-3}\times 8^{-2}\times8^5

We need to solve the given expression.

Now We know that when base of the exponents then the law of indices applied for the same.

Now According to Law of Indices.

x^a\times x^b = x^{a+b}

On Solving the above expression we get;

8^{-3+(-2)+5}\\\\8^{-3-2+5}\\\\8^{-5+5}\\\\8^0\\\\\textrm{Now Again by law of indices;}\\\\a^0 =1\\\\Hence\ 8^0 = 1

Hence The Simplified form of given expression is 1.

5 0
3 years ago
The vertices of polygon ABCD are at A(1, 1), B(2, 3), C(3, 2), and D(2, 1). ABCD is reflected across the x-axis and translated 2
Lana71 [14]

-- Reflecting across the x-axis makes all the x-coordinates the negative of
what they were before the reflection.  The y-coordinates don't change.

-- Translating 2 units up makes all the y-coordinates 2 greater than
they were before the translation.  The x-coordinates don't change.

You didn't give us a list of new coordinates, so there's nothing
to match with.
8 0
3 years ago
Given: △ABC, AB=5sqrt2 <br> m∠A=45°, m∠C=30°<br> Find: BC and AC
Marysya12 [62]

BC is 10 units and AC is 5+5\sqrt{3} units

Step-by-step explanation:

Let us revise the sine rule

In ΔABC:

  • \frac{AB}{sin(C)}=\frac{BC}{sin(A)}=\frac{AC}{sin(B)}
  • AB is opposite to ∠C
  • BC is opposite to ∠A
  • AC is opposite to ∠B

Let us use this rule to solve the problem

In ΔABC:

∵ m∠A = 45°

∵ m∠C = 30°

- The sum of measures of the interior angles of a triangle is 180°

∵ m∠A + m∠B + m∠C = 180

∴ 45 + m∠B + 30 = 180

- Add the like terms

∴ m∠B + 75 = 180

- Subtract 75 from both sides

∴ m∠B = 105°

∵ \frac{AB}{sin(C)}=\frac{BC}{sin(A)}

∵ AB = 5\sqrt{2}

- Substitute AB and the 3 angles in the rule above

∴ \frac{5\sqrt{2}}{sin(30)}=\frac{BC}{sin(45)}

- By using cross multiplication

∴ (BC) × sin(30) = 5\sqrt{2} × sin(45)

∵ sin(30) = 0.5 and sin(45) = \frac{1}{\sqrt{2}}

∴ 0.5 (BC) = 5

- Divide both sides by 0.5

∴ BC = 10 units

∵ \frac{AB}{sin(C)}=\frac{AC}{sin(B)}

- Substitute AB and the 3 angles in the rule above

∴ \frac{5\sqrt{2}}{sin(30)}=\frac{AC}{sin(105)}

- By using cross multiplication

∴ (AC) × sin(30) = 5\sqrt{2} × sin(105)

∵ sin(105) = \frac{\sqrt{6}+\sqrt{2}}{4}

∴ 0.5 (AC) = \frac{5+5\sqrt{3}}{2}

- Divide both sides by 0.5

∴ AC = 5+5\sqrt{3} units

BC is 10 units and AC is 5+5\sqrt{3} units

Learn more:

You can learn more about the sine rule in brainly.com/question/12985572

#LearnwithBrainly

6 0
3 years ago
I can't find area of the triangle
Andreas93 [3]

Answer:

First do the Base multiplied by the Height.

After divide by 2

Step-by-step explanation:


7 0
3 years ago
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Given a set A={G, 5, 6 }, answer the following questions:
AleksandrR [38]

Answer:

Letter A ang sagot bata maniwala sa trust

7 0
2 years ago
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