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Zinaida [17]
2 years ago
6

Ajar has 20 marvels three green 12 blue five real what is the probability of randomly choosing a red and then a green marble

Mathematics
1 answer:
laila [671]2 years ago
3 0

The answer is 3 I work it out

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What is the value of x?<br> x + 5 = - 6x - 16
exis [7]
X +5 = -6x - 16
add 16 to both sides
x+21 = -6x
add 6x to both sides
7x+21=0
factor out the seven
7(x+3)=0

if 7 times (x+3) = 0 then (x+3) must equal zero because 7 times 0 is 0

so x+3=0
subtract three from both sides
x= -3
4 0
3 years ago
Read 2 more answers
Vince helped the pep club make sandwiches to raise money. He put two in each of 30 bags and 5 sandwiches in 26 family bags, and
tamaranim1 [39]
Answer is 181 sandwiches
Working steps
Firstly you want to work backwards and turn in equation
30*2+26*4+17=X
So 60+104+17=X
That means 181=X

Enjoy
4 0
3 years ago
Point M is the midpoint of LN. LM = 7x - 12 and MN = 3x + 16. Find LM.
likoan [24]
Since point M is the midpoint of LN, LM and MN are equivalent in length.

7x - 12 = 3x + 16 (LM=MN)

7x = 3x + 28

4x = 28

x = 7

Now that we know the value of x, we can find the value of LM by plugging the value in the equation.

LM = 7(7) - 12

LM = 49 - 12

LM = 37

4 0
3 years ago
In a list of households, own homes and do not own homes. Five households are randomly selected from these households. Find the p
Paladinen [302]

Answer:

The probability of success for this case would be:

p =\frac{9}{15}= 0.6 representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=15, p=0.6)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

And we want this probability:

P(X=3)

And uing the probability mass function we got:

P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165

Step-by-step explanation:

Adduming the following info: In a list of 15 households, 9 own homes and 6 do not own homes. Five households are randomly selected from these 15 households. Find the probability that the number of households in these 5 own homes is exactly 3.

Round your answer to four decimal places

P (exactly 3)=

Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Solution to the problem

The probability of success for this case would be:

p =\frac{9}{15}= 0.6 representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=15, p=0.6)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

And we want this probability:

P(X=3)

And uing the probability mass function we got:

P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165

5 0
3 years ago
kims age is twice of her sister when you add to her sisters age you get 3 how old is each sister (a) write an equation that repr
Lina20 [59]
Kim is 2. Her sister is 1 years old. 2+1=3
6 0
3 years ago
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