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Sati [7]
3 years ago
10

How do you write 888,000,000 in science notation form

Mathematics
2 answers:
VLD [36.1K]3 years ago
7 0
8.88 x 10^8

To find out the number used in the scientific notation, move the decimal point to where there is one number on the left, giving us 8.88. From then, count the amount of times the decimal moved, which is 8, and there's your scientific notation
alexgriva [62]3 years ago
4 0

888,000,000 = 8.88*10^{8}

In scientific notation, what we do is we break up a number leaving only numbers that are more than 0, and multiply that value by a power of 10 to represent the 0's that where there before.

In this case, we got only 888 (numbers higher than 0) and transformed it to 8.88. After that we transformed all the 0's into a power of ten, which would be 10^{8} (1,000,000).


Hope it helped,


BioTeacher101

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Answer:

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Step-by-step explanation:

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22. The y-intercept is (0, 0), or simply 0. If you look at the graph you can see that the line crosses the y-axis at the origin. This makes the y-intercept equal to 0.

23. The slope tells you that the student makes $50 every week. The y-intercept is 0. Using the formula y=mx+b, an appropriate equation would be y=50x.

24. The equation found in problem 23 can me used to determine how much a student makes (y) after "x" weeks. Substitute 52 for x to solve for y. This becomes y=50(52). This can be simplified to y=2600. This means that after 52 weeks, the student will have made $2,600.

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3 years ago
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Step-by-step explanation:

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3 years ago
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 144 millimeters,
valentinak56 [21]

Answer:

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Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample  means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean  is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

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<em>σ</em> = 7 mm

<em>n</em> = 50.

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