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lana [24]
3 years ago
9

Help plz... Davidmedulla... I mean you in particular

Mathematics
1 answer:
kap26 [50]3 years ago
5 0

Answer:

1. 2x

2. 22

Step-by-step explanation:

question 1

f(x)-g(x)

5x-3-(3x-3)

5x-3-3x+3

5x-3x-3+3

2x+0

2x

question 2

f(x)=y

f(-4)= -5(-4)+ (-4/-2)

= 20 + 2

=22

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Hence, the value of the digit 4 will be i.e. 40 or forty. Example 1: Work out the place value, face value and value of 6 in the number 56,523.22.

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Help ASAP:Solve : 0.84+91.279
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92.119

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How many lines of symmetry does this figure have?
Sergeeva-Olga [200]

Answer:

2

Step-by-step explanation:

There are two lines of symmetry and here I list them:

1) The first is a horizontal line that divides the square in to even parts such that the top part is the projection of the down one trough the symmetry line (and vice versa).

2) The second one is the vertical line that divides the square in two even sides. Note that this line will also divide both stars at half. The left side will be projected on the right one (and vice versa) trough the symmetry line.

A third line could be thought to be a diagonal between opposite vertices, but notice that the stars projection won't by symmetric in this case.

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4 0
3 years ago
Answer correct you get brainliest answer​
zloy xaker [14]

Answer:

y =  {x}^{2}  - 2

Or if you want with the value of h too.

y =  {(x - 0)}^{2}  - 2

Step-by-step explanation:

y = a {(x - h)}^{2}  + k

Find the value of h and k by using the formula.

h =  -  \frac{b}{2a}  \\ k =  \frac{4ac -  {b}^{2} }{4a}

From y = x²-2

a = 1 \\ b = 0 \\ c =  - 2

Substitute these values in the formula.

h =  -  \frac{0}{2(1)}  \\ h = 0

Therefore, h = 0.

k =  \frac{4(1)( - 2) -  {0}^{2} }{4(1)}  \\ k =  \frac{ - 8}{4}  \\ k =  - 2

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

y = a {(x - h)}^{2}  + k \\ y = 1 {(x - 0)}^{2}  - 2 \\ y =  {(x)}^{2}  - 2 \\ y =  {x}^{2}  - 2

These type of equation where b = 0 can also be both standard and vertex form.

4 0
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