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Sindrei [870]
3 years ago
10

Please help Explanation will be appreciated thanks,

Mathematics
1 answer:
Genrish500 [490]3 years ago
4 0

Answer: A; 6.3%

Step-by-step explanation:

Problem 1

For the first problem, we first want to find y so that we can plug it into the expression.

We can use elimination method for the system of equations to solve.

3x+3y=21

3x-y=5

We subtract both equations to eliminate x.

4y=16                                        [divide both sides by 4]

y=4

Now that we know y, we can plug it into the expression.

\frac{4}{2} -3                                         [divide]

2-3                                         [subtract]

-1

We know that the answer is A.

--------------------------------------------------------------------------------------------------------

Problem 2

For the second problem, we need to know how to calculate percent error. The formula for precent error is \frac{|measured-exact|}{exact} *100%. We know that the exact value is 80 because the buyer was supposed to given 80. 75 is the measured value because that was what the buyer was given.

\frac{|75-80|}{80} *100%                               [subtract]

\frac{|-5|}{80} *100%                                   [solve absolue value]

\frac{5}{80} *100%                                     [divide]

0.0625*100%                               [multiply]

6.25

Since the problem said to round to one decimal place, we know that the answer is 6.3%.

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Rearrange 2y+6x=8 to make y the subject of the formula
Tomtit [17]

Answer:

y= 3x+4

Step-by-step explanation:

2y-6x=8

add 6x to each side

2y-6x+6x=6x+8

2y= 6x+8

divide each side by 2

2y/2 = 6x/2 + 8/2

y= 3x+4

4 0
2 years ago
Read 2 more answers
The following histogram shows the exam scores for a Prealgebra class. Use this histogram to answer the questions.Prealgebra Exam
Contact [7]

Answer:

The number of the class containing the  largest score can be found in frequency  24 and the class is  98 - 103

For the third class 78 - 83 ; the upper limit = 83

The class width for this histogram 5

The number of students that took the exam simply refers to the frequency is  84

The percentage of students that scored higher than 95.5 is 53%

Step-by-step explanation:

The objective of this question is to use the following histogram that shows the exam scores for a Pre-algebra class to answer the question given:

NOW;

The table given in the question can be illustrated as follows:

S/N           Class                Score          Frequency

1                 68  - 73            70.5           0

2                73 - 78             75.5           4

3                78 - 83             80.5           8

4                83 - 88             85.5           12

5                88 - 93            90.5           16

6                93 - 98            95.5           20

<u>7                98 - 103           100.5          24                            </u>

TOTAL:                                                 84

<u>                                                                                             </u>

<u />

a) The number of the class containing the  largest score can be found in frequency  24 and the class is  98 - 103

b) For the third class 78 - 83 ; the upper limit = 83  ( since the upper limit is derived by addition of  5 to the last number showing  in the highest value specified by the number in the class interval which is 78 ( i.e 78 + 5 = 83))

c)   The class width for this histogram 5 ; since it  is the difference  between the upper and lower boundaries  limit of the given class.

So , from above the difference in any of the class will definitely result into 5

d) The number of students that took the exam simply refers to the frequency ; which is (0+4+8+12+16+20+24) = 84

e) Lastly; the percentage of students that scored higher than 95.5 is ;

⇒\dfrac{20+24}{84} *100

= 0.5238095 × 100

= 52.83

To the nearest percentage ;the percentage of students that scored higher than 95.5 is 53%

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ioda

Answer:

45

Step-by-step explanation:

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50 points and a BRAINLIEST if you answer correctly! Pls Pls help!
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Answer:

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Step-by-step explanation:

Numbers Given are:

1 1/2, 2 1/2, 1 2/3, and 2 5/6

The result at the end of all the math is 2 5/6.

1 2/3 + 2 5/6 = 4 1/2

Divide 4 1/2 by 1 2/3 to get 2 7/10.

Subtract 2 2/3 from 2 7/10 to get 1/5.

Multiply 1/5 by 1 1/2 to get 3/10.

So the number they thought of was 3/10.

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