The volume of a square pyramid is (1/3)(area of base)(height of pyramid).
Here the area of the base is (10 ft)^2 = 100 ft^2.
13 ft is the height of one of the triangular sides, but not the height of the pyramid. To find the latter, draw another triangle whose upper vertex is connected to the middle of one of the four equal sides of the base by a diagonal of length 13 ft. That "middle" is 5 units straight down from the upper vertex. Thus, you have a triangle with known hypotenuse (13 ft) and known opposite side 5 feet (half of 10 ft). What is the height of the pyramid?
To find this, use the Pyth. Thm.: (5 ft)^2 + y^2 = (13 ft)^2. y = 12 ft.
Then the vol. of the pyramid is (1/3)(area of base)(height of pyramid) =
(1/3)(100 ft^2)(12 ft) = 400 ft^3 (answer)
Answer:
yetrygegegegr
Step-by-step explanation:
Answer:
Step-by-step explanation:
49 | 43 | 92
75 | 38 | 113
124 | 81 | 205
The Law of Cosines would be your best bet here, since the unknown side is opposite the known angle 110 degrees.
|AC|^2 = (8 in)^2 + (23 in)^2 - 2(8 in)(23 in)*cos 110 degrees
= 64 in^2 + 529 in^2 - (368 in^2)*(-0.342)
= 593 in^2 + 126 in ^2 approximately
= 719 in^2 approximately
Then the length of side AC is approx. √(716 in^2) = 27 in
Answer:
B.
Step-by-step explanation:
