We assume the probability on each side is equally probable with probability 1/5.
sum=4 has outcomes:{1,4; 2,3; 3,2; 4,1} 4 possible outcomes
sum=8 has outcomes:{3,5; 4,4; 5,3} 3 possible outcomes.
Total possible outcomes = 5*5=25
there probability of rolling a sum of 4 or 8, by the law of addition, equals
4/25+3/25=7/25
Note: a regular (i.e. fully symmetric) five-sided solid does not exist, so there has to be asymmetry among the probabilities of the five possible outcomes. In addition, it does not have a "top" face, so that makes rolling a five-sided solid a little more difficult to visualize.
It means different digits.
W=50 would count as one of the digits.
Now you have to figure out what “XYZ” is.
Take x-2 and insert it into 2x^2 + 3x-2 where the x is located
2x^2 + 3x-2
2(x-2)^2 + 3(x-2)-2
Now work out 2(x-2)^2 + 3(x-2)-2 also follow PEMDAS
2(x-2)^2 + 3(x-2)-2
Since (x-2)^2 is an Exponent, lets work with that first and expand (x-2)^2.
(x-2)^2
(x -2)(x-2)
x^2 -4x + 4
Now Multiply that by 2 because we have that in 2(x-2)^2
(x-2)^2 = x^2 -4x + 4
2(x-2)^2 = 2(x^2 -4x + 4)
2(x^2 -4x + 4) = 2x^2 - 8x + 8
2x^2 - 8x + 8
Now that 2(x-2)^2 is done lets move on to 3(x-2).
Use the distributive property and distribute the 3
3(x-2) = 3x - 6
All that is left is the -2
Now lets put it all together
2(x-2)^2 + 3(x-2)-2
2x^2 - 8x + 8 + 3x - 6 - 2
Now combine all our like terms
2x^2 - 8x + 8 + 3x - 6 - 2
Combine: 2x^2 = 2x^2
Combine: -8x + 3x = -5x
Combine: 8 - 6 - 2 = 0
So all we have left is
2x^2 - 5x
The answers is 14 if you follow the equation i just did it on a calculator (attached)
