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2 years ago

Solve the equation by the Quadratic Formula. x^2+3=9x

Mathematics

2 answers:

Nadya [2.5K]2 years ago

5 0

Answer:

Step-by-step explanation:

Rearrange the given x^2+3=9x in standard quadratic form:

1x^2 - 9x +3 = 0

Then the three coefficients are a = 1, b = -9 and c = 3.

The discriminant is √(b^2 - 4ac), or √(81 - [1][3]), or √78.

± √78

Thus, the roots are x = ----------------

stiks02 [169]2 years ago

3 0

Step-by-step explanation:

the 9x from the equation can be shifted into the equation and therefore x² + 3 = 9x can be also written as

x² - 9x + 3 = 0

then using the quadratic formula

$x = \frac{ - b \frac{ + }{ - } \sqrt{b {}^{2} - 4ac } }{2a}$

a = 1

b = -9

c = 3

substitute the values into the equation ,

insert it in your scientific calculator and you will have the answer of

x = 8.65 or x = 0.35

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Joe deposits $700 into an account that pays simple interest at a rate of 4% per year. How much will he be paid in the first 3 ye

nata0808 [166]

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784

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2 years ago

The residents of a city voted on whether to raise property taxes. The ratio of yes votes to no votes was 7 to 5 . If there were

Nitella [24]

Answer: 6456

Step-by-step explanation:

Ratio of yes to no= 7:5

Number if yes= 3766

Since total number of yes is 3766. To find the total number of votes, 3766 / (7/7+5)

= 3766/ (7/12)

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3 years ago

Factorise (x-y)^2-(x-y)^3=?

bogdanovich [222]

Answer:

$\left(x-y\right)^2\left(1-x+y\right)$

Step-by-step explanation:

You factor out the common term first.

You should get the equation below.

$\left(x-y\right)^2\left(1-\left(x-y\right)\right)$

then you get rid of the negative inside $\left(1-\left(x-y\right)\right)$

and will be simplified to this.

$\left(x-y\right)^2\left(1-x+y\right)$

4 0

2 years ago

10+6÷3+2×8=

lawyer [7]

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7 0

2 years ago

Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments

kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

$\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}$

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

$\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}$

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

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9 months ago