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zepelin [54]
3 years ago
8

Evan earns $18 per hour. how much will he earn per hour if he gets a 5% raise?

Mathematics
1 answer:
agasfer [191]3 years ago
6 0
18·0.05= 0.9
0.9+18= 18.90
Even will earn $18.90 dollars an hour.
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x^2(x-1)-25(x-1)=(x-1)(x^2-25)\\\\=(x-1)(x^2-5^2)=(x-1)(x-5)(x+5)\\\\Used:\ a^2-b^2=(a-b)(a+b)
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3 years ago
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If y varies directly as x, and y is 48 when x is 6, give an expression can be used to find the value of y when x is 2?
Contact [7]
As both x and y varies directly and also when y is 48 then x is 6 so the expression must be
y = 8x

so when x = 2 then according to relation ...

y = 8x
y = 8*2
y = 16


hope it helped
7 0
3 years ago
"la temperatura mas baja conocida en la tierra es de 273° bajo cero mientras que la temperatura promedio de la superficie de la
skelet666 [1.2K]

Answer:

Variación de temperatura: 310°C

Step-by-step explanation:

La variación de temperatura entre la temperatura más baja conocida en la tierra (-273°C = 273° bajo cero) y la temperatura promedio de la tierra (37°C) será el valor absoluto de la diferencia de estos dos valores, es decir:

Variación de temperatura: |-273°C - 37°C|

Variación de temperatura: |-310°C|

<em>Como el valor absoluto de un número negativo es su valor positivo (|-x| = x)</em>

<h3>Variación de temperatura: 310°C</h3>
4 0
3 years ago
Plz help me, URGENT!! 15 points!
bulgar [2K]

Answer:

i just neeed the points

Step-by-step explanation:

5 0
3 years ago
After a baseball is hit, the height h (in feet) of the ball above the ground t seconds after it is hit can be approximated by th
lubasha [3.4K]

Answer:

The ball will take 4.05 seconds to hit the ground.

Step-by-step explanation:

we have

h=-16t^{2}+64t+3

This is a quadratic equation (vertical parabola) open down

The vertex is a maximum

we know that

The ball hit the ground when h=0

Solve the quadratic equation

For h=0

-16t^{2}+64t+3=0

The formula to solve a quadratic equation of the form

at^{2} +bt+c=0 is equal to

t=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16t^{2}+64t+3=0  

so

a=-16\\b=64\\c=3

substitute in the formula  

t=\frac{-64(+/-)\sqrt{64^{2}-4(-16)(3)}} {2(-16)}

t=\frac{-64(+/-)\sqrt{4,288}} {-32}

t=\frac{64(-)\sqrt{4,288}} {32}=-0.05\ sec  ---> the time cannot be a negative number

t=\frac{64(+)\sqrt{4,288}} {32}=4.05\ sec

therefore

The ball will take 4.05 seconds to hit the ground.

4 0
3 years ago
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