All categories

3 years ago

The original price of water skis was $200. What is the percent of discount?

Mathematics

1 answer:

nikitadnepr [17]3 years ago

3 0

You need to tell how many percent you will discount and then find the new price

You might be interested in

Please please help please

Readme [11.4K]

Step-by-step explanation:

its .86 which is closer to .87

so choose the first one

7 0

2 years ago

Read 2 more answers

A video game console that is normally priced at 269.99 has been marked down by 33% of its original price. If the sales tax is 8.

larisa86 [58]

Answer:

$5.99

Step-by-step explanation:

I am Majoring in math and Personal Finance

7 0

2 years ago

Please help me on this will give you brainliest!!

vovangra [49]

Answer:

∠3 would be 134° because it is alternate interior to ∠5

∠2 would be 46° because it is supplementary to ∠1

Hope this helped

4 0

2 years ago

The weight distribution of parcels sent in a certain manner is normal with mean of 12 lb and standard deviation of 3 lb. The par

kicyunya [14]

Answer:

21.16

Step-by-step explanation:

Starting from the theory we have the following equation:

$fi*P(x$

Using the data supplied in the exercise, we have subtracting the mean and dividing by the standard deviation:

$P( z \leq \frac{c-1-12}{3.5}) =0.99/fi$

solving for "c", knowing that fi is a tabulating value:

$\frac{c-13}{3.5}=0.99/fi\\\frac{c-13}{3.5}=2.33\\c-13=2.33*3.5\\c = 8.155 +13\\c = 21.155$

therefore the value of c is equal to 21.16

8 0

3 years ago

Find the angles between -pi and pi that satisfy:<br><br> (−√3) sin(v)+cos(v)=√3

MAXImum [283]

Observe that

$\sin\left(\dfrac\pi6-v\right)=\sin\dfrac\pi6\cos v-\cos\dfrac\pi6\sin v=\dfrac12\cos v-\dfrac{\sqrt3}2\sin v$

In the original equation, divide both sides by $\dfrac12$ :

$-\sqrt3\sin v+\cos v=\sqrt3\implies\dfrac12\cos v-\dfrac{\sqrt3}2\sin v=\dfrac{\sqrt3}2$

$\implies\sin\left(\dfrac\pi6-v\right)=\dfrac{\sqrt3}2$

Next,

$\sin x=\dfrac{\sqrt3}2\implies x=\dfrac\pi3+2n\pi,x=\dfrac{2\pi}3+2n\pi$

where $n$ is any integer. Then

$\sin\left(\dfrac\pi6-v\right)\implies v=-\dfrac\pi6-2n\pi,v=-\dfrac\pi2-2n\pi$

Fix $n=0$ to ensure $-\pi$ , so that

$v=-\dfrac\pi6,v=-\dfrac\pi2$

3 0

3 years ago