Answer:
Idk if its multiple choice but you can do 1 of 2 ways theres using distance formula =√(5-3)sq+(1-4)sq
=√4+9
=√13 <--
or
3.6 units
Given: The two points that are P(5,1) and Q(3,4).
To find: The distance between these two points.
Solution: It is given that there are two points that are P(5,1) and Q(3,4).
The distance between these two points can be found out as using the distance formula that is: 3.6
Thus, the distance between the given two points is 3.6 units.
So you choose 13 or 3.6 Hope this helps :)
Answer:
2.87 = AC
Step-by-step explanation:
Since this is a right triangle we can use trig functions
sin theta = opp / hyp
sin 35 = AC /5
5 sin 35 = AC
2.867882182= AC
To the nearest hundredth
2.87 = AC
Answer:
3x times 3x times 3x times 3x + x^3 + 3x times 2x times 3x times 2x + 2x
or
x^3 + 2x^3 + 3x^6
Step-by-step explanation:
3x^4 + x^3 + 6x^2 + 2x
3x times 3x times 3x times 3x + x^3 + 6x times 6x + 2x
3x times 3x times 3x times 3x + x^3 + 3x times 2x times 3x times 2x + 2x
x^3 + 2x^3 + 3x^6
The answer for 4 is 12..
hope it helps u..
have a great day ahead! :)
The correct answer is true:)
