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3 years ago

24% of a number is what fraction of that number?

Mathematics

2 answers:

Arada [10]3 years ago

3 0

6/25 , the word percent can be broken down into two sub units per and cent meaning per for every cent i.e. 100.

Alex_Xolod [135]3 years ago

3 0

Answer:

24/100 or 6/25

Step-by-step explanation:

Remember that a percentage is a number out of a hundred. So 24% of a number in a fraction form would be 24/100. 24% is equal to 0.24 and since it ends in the hundreds place the fraction's denominator would be 100. If your teacher requires the simplified answer if would be 6/25 because 24 divided by 4 is 6 and 100 divided by 4 is 25.

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34. The number of songs that an MP3 player can

neonofarm [45]

Answer:

Step-by-step explanation:

640

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2 years ago

Positionx (m)

9966 [12]

Answer:

A. 3.0 m/s

Step-by-step explanation:

Based on the graph,

velocity = Area of the graph

$v = \frac{y1 - y2}{x1 - x2}$

(y : position and x : time)

Let y1 = 2m and y2 = 14m,

t1 = 0s and t2 = 4s

v = (14 - 2)m/(4-0)s

= 12m/4s

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6 0

3 years ago

Read 2 more answers

14. Please help. What is the length of PQ⎯⎯⎯⎯⎯⎯⎯⎯?<br> Enter the correct value.

Pepsi [2]

Answer:

The correct value is 5.

5 0

3 years ago

Find four distinct complex numbers (which are neither purely imaginary nor purely real) such that each has an absolute value of

Luda [366]

Answer:

0.5 + 2.985i
1 + 2.828i
1.5 + 2.598i
2 + 2.236i

Explanation:

Complex numbers have the general form a + bi, where a is the real part and b is the imaginary part.

Since, the numbers are neither purely imaginary nor purely real a ≠ 0 and b ≠ 0.

The absolute value of a complex number is its distance to the origin (0,0), so you use Pythagorean theorem to calculate the absolute value. Calling it |C|, that is:

$|C| = \sqrt{a^2+b^2}$

Then, the work consists in finding pairs (a,b) for which:

$\sqrt{a^2+b^2}=3$

You can do it by setting any arbitrary value less than 3 to a or b and solving for the other:

$\sqrt{a^2+b^2}=3\\ \\ a^2+b^2=3^2\\ \\ a^2=9-b^2\\ \\ a=\sqrt{9-b^2}$

I will use b =0.5, b = 1, b = 1.5, b = 2

$b=0.5;a=\sqrt{9-0.5^2}=2.958\\ \\b=1;a=\sqrt{9-1^2}=2.828\\ \\b=1.5;a=\sqrt{9-1.5^2}=2.598\\ \\b=2;a=\sqrt{9-2^2}=2.236$

Then, four distinct complex numbers that have an absolute value of 3 are:

0.5 + 2.985i
1 + 2.828i
1.5 + 2.598i
2 + 2.236i

4 0

3 years ago

A forestal station receives the locations of two fires, one of them in a forest located 11 Km heading N69°W from the station. Th

loris [4]

Answer:

30.7 km

Step-by-step explanation:

The distance between the two fires can be found using the Law of Cosines. For ΔABC in which sides 'a' and 'b' are given, along with angle C, the third side is ...

c = √(a² +b² -2ab·cos(C))

The angle measured between the two fires is ...

180° -(69° -35°) = 146°

and the distance is ...

c = √(11² +21² -2(11)(21)cos(146°)) ≈ √945.015

c ≈ 30.74

The straight-line distance between the two fires is about 30.7 km.

8 0

2 years ago