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trasher [3.6K]
3 years ago
15

What is 63/80 as a decimal

Mathematics
1 answer:
Kaylis [27]3 years ago
7 0
To get 63/80 converted to decimal, you simply divide 63 by 80. Don't worry. You don't need to get the calculator out, because I did this for you.

63/80 as a decimal is:

<span>0.787500</span>
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(Anderson, 1.14) Assume that P(A) = 0.4 and P(B) = 0.7. Making no further assumptions on A and B, show that P(A ∩ B) satisfies 0
Goshia [24]

Answer with Step-by-step explanation:

We are given that

P(A)=0.4 and P(B)=0.7

We know that

P(A)+P(B)+P(A\cap B)=P(A\cup B)

We know that

Maximum value of P(A\cup B)=1 and minimum value of P(A\cup B)=0

0\leq P(A\cup B )\leq 1

0\leq P(A)+P(B)-P(A\cap B)\leq 1

0\leq 0.4+0.7-P(A\cap B)\leq 1

0\leq 1.1-P(A\cap B)\leq 1

0\leq 1.1-P(A\cap B)

P(A\cap B)\leq 1.1

It is not possible that P(A\cap B) is equal to 1.1

1.1-P(A\cap B)\leq 1

-P(A\cap B)\leq 1-1.1=-0.1

Multiply by (-1) on both sides

P(A\cap B)\geq 0.1

Again, P(A\cup B)\geq P(B)

0.4+0.7-P(A\cap B)\geq 0.7

1.1-P(A\cap B)\geq 0.7

-P(A\cap B)\geq -1.1+0.7=-0.4

Multiply by (-1) on both sides

P(A\cap B)\leq 0.4

Hence, 0.1\leq P(A\cap B)\leq 0.4

3 0
3 years ago
Estimate 55+3<br> to the hundred the<br> place,
pentagon [3]

Answer:

100

Step-by-step explanation:

8 0
2 years ago
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PLEASE HELP ME!!!!! A quadrilateral with vertices (0,0), (4,0), (3,2), (1,1) is mapped to a quadrilateral with vertices (6,3).(-
Murljashka [212]

Answer:

( 2,1) is the center of dilation and -2 is the scale factor

Step-by-step explanation:

We can use the formula

A' = k( x-a) +a, k( y-b)+b  where ( a,b) is the center of dilation and k is the scale factor

(0,0) becomes (6,3)

( 6,3) =  k( 0-a) +a, k( 0-b)+b

6 = -ka+a

3 = -kb+b

We also have

(4,0) becomes (-2,3)

( -2,3) =  k( 4-a) +a, k( 0-b)+b

-2 =4k -ka+a

3 = -kb+b

Using these two equations

6 = -ka+a

-2 =4k -ka+a

Subtracting the top from the bottom

-2 =4k -ka+a

-6 = ka -a

-------------------

-8 = 4k

Divide by 4

-8/4 = 4k/4

-2 = k

Now solving for a

6 = -ka +a

6 = - (-2)a +a

6 = 2a+a

6 = 3a

Divide by 3

6/3 =3a/3

2=a

Now finding b

3 = -kb+b

3 = -(-2)b+b

3 = 2b+b

3 = 3b

b=1

6 0
3 years ago
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The curve with equation y=ax^2+bx has a gradient of 3 at the point (2,-2). Find the values of a and b.
Airida [17]

Answer:

a = 2, b = - 5

Step-by-step explanation:

Given

y = ax² + bx

\frac{dy}{dx} is the measure of the slope at x = a

Differentiate each term with respect to x using the power rule

\frac{d}{dx}(ax^{n} ) = nax^{n-1}

\frac{dy}{dx} = 2ax + b, hence

2ax + b = 3 at (2, - 2)

Substitute x = 2 into \frac{dy}{dx}

4a + b = 3 → (1) and substitute x = 2 into y

4a + 2b = - 2 → (2)

Subtract ( 1) from (2)

b = - 2 - 3 = - 5

Substitute b = - 5 into (1)

4a - 5 = 3 ( add 5 to both sides )

4a = 8 ( divide both sides by 4 )

a = 2

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Please answer this question fast in 2 minutes
Dafna1 [17]

Answer:

Angle 4 as it is across from 1 and is equal in size

Step-by-step explanation:

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