The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is 
<u>Solution:</u>
Given, two points are (-6, 6) and (-3, -9)
We have to find the midpoint of the segment formed by the given points.
The midpoint of a segment formed by
is given by:


Plugging in the values in formula, we get,

Hence, the midpoint of the segment is 
An Euler path, in a graph or multi graph, is a walk through the graph which uses every edge exactly once. An Euler circuit is an Euler path which starts and stops at the same vertex. Our goal is to find a quick way to check whether a graph (or multi graph) has an Euler path or circuit.
hope it helps
<h2>60,47,73</h2>
Step-by-step explanation:
Let the first angle be
degrees
Let the second angle be
degrees
Let the third angle be
degrees
It is given that sum of angles is
degrees.
so,
...(i)
It is given that sum of the measures of the second and third angles is two times the measure of the first angle.
...(ii)
It is given that the third angle is 26 more than the second.
...(iii)
using (ii) and (iii),


using (i),(ii) and (iii),





Answer: 30y + 15x
If x is for sneakers, and y is for high heels, plug 15 in for a and 30 in for b. This means that x is how many sneakers she buys, and y is how many high heels she buys. The equation altogether represents the total amount of her purchases.
we are given to simplify

Open the bracket and write the like terms together

when the bases are same then the exponents gets added
