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Iteru [2.4K]
3 years ago
8

The amount of potential energy, P, an object has is equal to the product of its mass, m, its height off the ground, h, and the g

ravitational constant, g. This can be modeled by the equation P = mgh. What is the equivalent equation solved for h?
A. (p/m)/g=h

B. p/mg=h

C. Pmg=h

D. p/(m/g)=h
Mathematics
2 answers:
Gwar [14]3 years ago
7 0

Answer:

B

Step-by-step explanation:

Don't know how to explain

shepuryov [24]3 years ago
6 0
Your answer should be B) p\mg=h just divide
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Answer:

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Step-by-step explanation:

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3 years ago
[(b+3)÷(a–2)](−4) if a=−5, b=6
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Answer:

36/7

Step-by-step explanation:

{(6+3)/(-5-2)}(-4)

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A camera has a listed price of $876.99 before tax. If the sales tax rate is 6.75%, find the total cost of the camera with sales
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3 years ago
Two friends argue about the calculated probability of flipping a coin to show heads three times in a row. steve mentions that ea
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Solution:

A coin is flipped three times,resulting three heads in a row.

Since Steve has mentioned that ,  each flip  of a coin is unconnected to the previous flip.

Two or more events are said to be independent if occurrence of one of them is not affected by the Occurrence of other.

This is an example of independent events.

In terms of probability, P (A∩B∩C)= P(A)×P(B)×P(C)

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3 years ago
An elementary ntimesn scaling matrix with k on the diagonal is the same as the ntimesn identity matrix with _______ exactly one
Dafna11 [192]

Answer:

exactly one, 0's, triangular matrix, product and 1.

Step-by-step explanation:

So, let us first fill in the gap in the question below. Note that the capitalized words are the words to be filled in the gap and the ones in brackets too.

"An elementary ntimesn scaling matrix with k on the diagonal is the same as the ntimesn identity matrix with EXACTLY ONE of the (0's) replaced with some number k. This means it is TRIANGULAR MATRIX, and so its determinant is the PRODUCT of its diagonal entries.​ Thus, the determinant of an elementary scaling matrix with k on the diagonal is (1).

Here, one of the zeros in the identity matrix will surely be replaced by one. That is to say, the determinants = 1 × 1 × 1 => 1. Thus, it is a a triangular matrix.

3 0
3 years ago
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