So how do you draw 2 degree angle

You want to get from a point A on the straight shore of the beach to a buoy which is 54 meters out in the water from a point B o

anyanavicka [17]

Answer:

$x =\dfrac{45 \sqrt{6}}{ 2}$

Step-by-step explanation:

From the given information:

The diagrammatic interpretation of what the question is all about can be seen in the diagram attached below.

Now, let V(x) be the time needed for the runner to reach the buoy;

∴ We can say that,

$\mathtt{V(x) = \dfrac{70-x}{7}+\dfrac{\sqrt{54^2+x^2}}{5}}$

In order to estimate the point along the shore, x meters from B, the runner should stop running and start swimming if he want to reach the buoy in the least time possible, then we need to differentiate the function of V(x) and relate it to zero.

i.e

The differential of V(x) = V'(x) =0

= $\dfrac{d}{dx}\begin {bmatrix} \dfrac{70-x}{7} + \dfrac{\sqrt{54^2+x^2}}{5} \end {bmatrix}= 0$

$-\dfrac{1}{7}+ \dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}=0$

$\dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}$

$\dfrac{5x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}$

$\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{\dfrac{7}{5}}$

$\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{5}{7}$

squaring both sides; we get

$\dfrac{x^2}{54^2+x^2}= \dfrac{5^2}{7^2}$

$\dfrac{x^2}{54^2+x^2}= \dfrac{25}{49}$

By cross multiplying; we get

$49x^2 = 25(54^2+x^2)$

$49x^2 = 25 \times 54^2+ 25x^2$

$49x^2-25x^2 = 25 \times 54^2$

$24x^2 = 25 \times 54^2$

$x^2 = \dfrac{25 \times 54^2}{24}$

$x =\sqrt{ \dfrac{25 \times 54^2}{24}}$

$x =\dfrac{5 \times 54}{\sqrt{24}}$

$x =\dfrac{270}{\sqrt{4 \times 6}}$

$x =\dfrac{45 \times 6}{ 2 \sqrt{ 6}}$

$x =\dfrac{45 \sqrt{6}}{ 2}$

8 0

2 years ago

Quadrilateral ABCD is inscribed in this circle.

Sunny_sXe [5.5K]

Answer: $m\angle A=116\°$

Step-by-step explanation:

The missing figure is attached.

For this exercise it is important to remember that, by definition, the opposite interior angles of an inscribed quadrilateral are supplementary, which means that their sum is 180 degrees.

Based on this, you can identify that the angle D and the angle B are opposite and, therefore, supplementary.

Knowing that, you can write the following equation:

$x+28\°=180\°$

Now you must solve for "x" in order to find its value. This is:

$x=180\°-28\°\\\\x=152\°$

Then:

$m\angle D=152\°$

You know that:

$m\angle A=(x-36)\°$

Therefore, since you know the value of "x", you can substitute it into $m\angle A=(x-36)\°$ and then you must evaluate, in order to find the measure of the angle A. This is:

$m\angle A=152\°-36\°\\\\m\angle A=116\°$

4 0

2 years ago

13) What is the simple interest and total amount earned on $4345 with an interest rate of

Annette [7]

Answer:

173.80 interest, 4518.80 total

Step-by-step explanation:

4345 X .03(3%)=130.35/year

130.35/12=10.8625/month

10.8625 x 16 months = 173.80 interest over 16 months

4345+173.80=4518.80 total amount

6 0

2 years ago

List the next 4 multiples of the unit fraction . 1/2 ___,___,___,___,

const2013 [10]

½ × 2 = 1
½ × 3 = 3/2
½ × 4 = 2
½ × 5 = 5/2

8 0

3 years ago

Read 2 more answers

A submarine started at 750 meters below sea level. It rose 50 meters per hour over a 4-hour period. Which expression represents

Cerrena [4.2K]

Answer:

$y(t) = 750 -50t$

Step-by-step explanation:

We want to model the position of the submarine as a function of time.

Notice that we have a constant amount. The initial depth: 750 meters

Then we have a factor that varies over time. Every hour the submarine ascends 50 meters. therefore as t increases the depth y(t) of the submarine decreases. Then the factor is:

-50t.

Where t represents the time in hours.

Then the equation that represents the new position of the submarine in relation to the level of the sea:

$y(t) = 750 -50t$

4 0

3 years ago

Read 2 more answers

So how do you draw 2 degree angle ​

So how do you draw 2 degree angle