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3 years ago

Please help me on this

Mathematics

1 answer:

Leni [432]3 years ago

4 0

5 7/8 is the answer to the problem

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Please help!!! I really need to solve this

nlexa [21]

This problem is already a bit more simple since they give you the amount of fabric per sock. Now, to solve, you will want to divide 9 3/4 by 5/6. However, if you don't have a calculator, it's rather inconvenient to solve with a fraction, so convert the fraction to a decimal, which should leave you as 9.75 divided by .83333333. Your final answer should be somewhere around 11.7 socks. Since you can't make 7/10 of a sock, your answer should be around 11 socks.

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2 years ago

Krystal puts three pencils in order from longest to shortest what is a fast way to order the same pencils from shortest to longe

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Swap the shortest and longest pencil's places. You don't have to move the middle pencil.

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3 years ago

Read 2 more answers

Name a chord shown in this diagram.

Gre4nikov [31]

Answer:

R to S

Step-by-step explanation:

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2 years ago

A horticulturist working for a large plant nursery is conducting experiments on the growth rate of a new shrub. Based on previou

valkas [14]

Answer:

$t=\frac{1.8-2}{\frac{0.5}{\sqrt{48}}}=-2.771$

The degrees of freedom are given by:

$df=n-1=48-1=47$

And the p value would be:

$p_v =P(t_{(47)}$

Since the p value is lower than the significance level we have enough evidence to conclude that the true mean for this case for the growth rate is less than 2cm per week

Step-by-step explanation:

Information given

$\bar X=1.8$ represent the sample mean for the growth

$s=0.5$ represent the sample standard deviation

$n=48$ sample size

$\mu_o =2$ represent the value that we want to compare

$\alpha=0.01$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean is less than 2cm per week, the system of hypothesis are :

Null hypothesis: $\mu \geq 2$

Alternative hypothesis: $\mu < 2$

Since we don't know the population deviation the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{1.8-2}{\frac{0.5}{\sqrt{48}}}=-2.771$

The degrees of freedom are given by:

$df=n-1=48-1=47$

And the p value would be:

$p_v =P(t_{(47)}$

Since the p value is lower than the significance level we have enough evidence to conclude that the true mean for this case for the growth rate is less than 2cm per week

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3 years ago

A food scientist is developing a new recipe. He needs it to have between 3 and 5 teaspoons of sugar per serving and between 3 an

Tema [17]

Answer:

aaaaaaaa nad its by

Step-by-step explanation:

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2 years ago