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Oksi-84 [34.3K]
4 years ago
6

Consider the relationship below, given . Which of the following best explains how this relationship and the value of sin can be

used to find the other trigonometric values? The values of sin and cos represent the legs of a right triangle with a hypotenuse of 1; therefore, solving for cos finds the unknown leg, and then all other trigonometric values can be found. The values of sin and cos represent the angles of a right triangle; therefore, solving the relationship will find all three angles of the triangle, and then all trigonometric values can be found. The values of sin and cos represent the angles of a right triangle; therefore, other pairs of trigonometric ratios will have the same sum, 1, which can then be used to find all other values. The values of sin and cos represent the legs of a right triangle with a hypotenuse of –1, since is in Quadrant II; therefore, solving for cos finds the unknown leg, and then all other trigonometric values can be found.
Mathematics
2 answers:
telo118 [61]4 years ago
7 0

Answer: It's A

Step-by-step explanation:

vova2212 [387]4 years ago
5 0

Answer:

The values of sin θ and cos θ represent the legs of a right triangle with a hypotenuse of 1; therefore, solving for cos θ finds the unknown leg, and then all other trigonometric values can be found.

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7 0
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100 POINTS please show your work
Anon25 [30]

Answer:

See below for answers and explanations (along with a graph)

Step-by-step explanation:

<u>Part A</u>

Set f(x)=0 and factor the expression by grouping:

f(x)=2x^2-3x-5\\\\0=2x^2-3x-5\\\\0=2x^2+2x-5x-5\\\\0=2x(x+1)-5(x+1)\\\\0=(2x-5)(x+1)

Use the Zero Product Property to find the x-intercepts:

0=2x-5\\5=2x\\x=\frac{5}{2}

0=x+1\\x=-1

Hence, the x-intercepts for the graph of f(x) are x=-1 and x=\frac{5}{2}.

<u>Part B</u>

Find the x-coordinate of the vertex:

x=-\frac{b}{2a}\\ \\x=-\frac{(-3)}{2(2)}\\\\x=\frac{3}{4}

Find the y-coordinate of the vertex:

f(\frac{3}{4})=2(\frac{3}{4})^2-3(\frac{3}{4})-5=-\frac{49}{8}

Hence, the vertex is (\frac{3}{4},-\frac{49}{8}). We can see from the positive leading coefficient of the function that the vertex will be a minimum because the parabola will open faced-up.

<u>Part C</u>

You can use the x-intercepts and vertex to plot points of the graph of the function. Additionally, you can throw in the y-intercept in as well. The y-intercept, in this case, is f(0)=2(0)^2-3(0)-5=-5, or (0,-5) as an ordered pair. See attached graph.

8 0
2 years ago
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