Answer:
Okapi 290 kg
Llama 160 kg
Step-by-step explanation:
Let weight of each llama be 
Let weight of each okapi be 
<em>Given, combined weight of 1 okapi and 1 llama is 450, we can write:</em>
<em>
</em>
<em>Also, average weight of 3 llama is 190 more than the average weight of 1 okapi, thus we can write:</em>
<em>
</em>
Now, substituting 2nd equation into 1st equation, we can solve for weight of 1 llama:

Each llama weights 160 kg, now using this and plugging into 2nd equation, we get weight of 1 okapi to be:

Each okapi weigh 290 kg
0.029= 2.9 x 10 power of negative 2
Answer:
The correct option is c.
Step-by-step explanation:
The percentage probability distribution is:
Size (X) Percentage
2 39.9
3 24.4
4 20.1
5 10.8
6 3.3
7 1.5
Total 100.0
Compute the probability that the size of the family is 4 or more as follows:
P (X ≥ 4) = P (X = 4) + P (X = 5) + P (X = 6) + P (X = 7)
= 0.201 + 0.108 + 0.033 + 0.015
= 0.357
Thus, the probability that the size of the family is 4 or more is 0.357.
The correct option is c.
find prime factors to get the inbetween numbers for product, and choose the one that has a difference of 20, and it should be 5 and 25, both requirements are met.