Answer:
Denote AH as height of triangle ABC, with H lies on BC.
Applying sine theorem:
AH/AC = sin 60
=> AH = AC x sin 60 = 47 x sqrt(3)/2 = 40.7
=> Area of triangle ABC is calculated by:
A = AH x BC x (1/2) = 40.7 x 30 x (1/2) = 610.5 = ~611
=> Option C is correct.
Hope this helps!
:)
To find the area of a rectangle, multiple the width by the length.
(And simply the fractions for a simpler equation)
For piece A:
The length 1 and 3/5 can be turned into an improper fraction by multiplying 1 by the denominator (5) and adding it to the numerator (3). 1 and 3/5 = 8/5
(3/4) • (8/5) = area
Multiple the numerators with each other and the denominators with each other (3 times 8 = 24) (4 times 5 = 20)
The area of piece A is 24/20
If you do the same for piece B:
(2/5) • (21/8) = area
The answer is 42/40
Answer:
The 2nd
Step-by-step explanation:
It shows the denominator of 3/4
Answer:
10 weeks
Step-by-step explanation:
20x+50=250
First subtract 50 from both sides, which gives you 20x=200
then divide 20 from both sides which gives you x=10
3/8 is0.375 so it would stay as 2 and 5/6 is 0.8333 so it rounds up to 9
So now do 2 times 9 = 18
