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N76 [4]
4 years ago
9

Write the equation of a line with a slope of −2 and a y-intercept of 5.

Mathematics
1 answer:
sergeinik [125]4 years ago
5 0
Y = mx + b
slope = m
y int = b

now we just sub
y = -2x + 5
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Please show your work someone !!!!!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!
DIA [1.3K]

Answer:

correct answer is (3)

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3 0
3 years ago
Use Definition 7.1.1, DEFINITION 7.1.1 Laplace Transform Let f be a function defined for t ≥ 0. Then the integral ℒ{f(t)} = ∞ e−
poizon [28]

f(t)=\begin{cases}\cos t&\text{for }0\le t

The Laplace transform is then

\mathcal L_s\{f(t)\}=\displaystyle\int_0^\infty f(t)e^{-st}\,\mathrm dt=\int_0^\pi e^{-st}\cos t\,\mathrm dt

Let I denote the integral we want to compute. Integrating by parts, setting

u=e^{-st}\implies\mathrm du=-se^{-st}\,\mathrm dt

\mathrm dv=\cos t\,\mathrm dt\implies v=\sin t

gives

\displaystyle I=e^{-st}\sin t\bigg|_{t=0}^{t=\pi}+s\int_0^\pi e^{-st}\sin t\,\mathrm dt

Integrate by parts again, setting

u=e^{-st}\implies\mathrm du=-se^{-st}\,\mathrm dt

\mathrm dv=\sin t\,\mathrm dt\implies v=-\cos t

Then

\displaystyle I=e^{-st}\sin t\bigg|_{t=0}^{t=\pi}+s\left(-e^{-st}\cos t\bigg|_{t=0}^{t=\pi}-s\int_0^\pi e^{-st}\cos t\,\mathrm dt\right)

I=e^{-st}(\sin t-s\cos t)\bigg|_{t=0}^{t=\pi}-s^2I

(s^2+1)I=s(e^{-\pi s}+1)

I=\dfrac s{s^2+1}(e^{-\pi s}+1)

7 0
3 years ago
Refer to the figure. Give a reason to justify the statement.
crimeas [40]

Answer: C OR A IS THE ANSWER

Step-by-step explanation:


5 0
3 years ago
10095 meters/seconds to miles/seconds
Valentin [98]
1,609 meters = 1 mile
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Therefore, <span>10095 meters/seconds = 6.3 miles/seconds</span>
8 0
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almond37 [142]

Answer:

2 7th graders prefer peperoni

4 8th graders prefer peperoni

7 7th graders prefer cheese

3 8th graders prefer cheese

Step-by-step explanation:

it does tell you the answer but you have to put it down, at least for me

8 0
3 years ago
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