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N76 [4]
4 years ago
9

Write the equation of a line with a slope of −2 and a y-intercept of 5.

Mathematics
1 answer:
sergeinik [125]4 years ago
5 0
Y = mx + b
slope = m
y int = b

now we just sub
y = -2x + 5
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What is the area of △JKL in square units? KJL is a triangle. The angle J is 94 degree and the angle L is 26 degree. Side JK is 2
Tamiku [17]

Answer:

426.07 square units

Step-by-step explanation:

Recall that for a triangle whose angles are A,B,C  with corresponding sides a, b, c, the area G of the triangle may be computed as

G = 1/2 ab Sin C

or

G = 1/2 bc Sin A

or

G = 1/2 ac Sin B

Going by this, recall that the sum of angles in a triangle is 180 hence

94 + 26 + K = 180

120 + K = 180

Subtract 120 from both sides

K = 180 - 120

K = 60 degrees

Given that JK = 24 and JL = 41

G = 1/2 * 24 * 41 Sin 60

= 426.07 square units

8 0
3 years ago
What is 4.4822x10 in scientific notation
skad [1K]

Answer:

4.4822x0

Hope this helps


8 0
4 years ago
Factorise:b+√b-12<br>An easy one.​
aalyn [17]

Answer:

Step-by-step explanation:

If you let b = x^2 the problem becomes a whole lot easier. Note that x = √b

x^2 + x - 12

Now factor this trinomial.

(x + 4)(x - 3)

Now put b back into the equation

(√b + 4)(√b - 3)

7 0
3 years ago
A rectangle is constructed with its base on the​ x-axis and two of its vertices on the parabola y equals = 100 100 minus −x squa
masha68 [24]

Answer:

Step-by-step explanation:

Given that a rectangle is constructed with its base on the x axis and two of its vertices on the parabola

y=100-x^2

This parabola has vertex at (0,100) and symmetrical about y axis.

Any general point above x axis can be written as (a,b) (-a,b) since symmetrical about yaxis.  

Hence coordinates of any rectangle are

(a,0) (-a,0), (a, 100-a^2), (-a, 100-a^2)

Length of rectangle = 2a and width = 100-a^2

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To find max area, use derivative test.

A' = 200-800a^2\\A"=-1600a

Hence maxima when first derivative =0

i.e. when a =2

Thus we find dimensions of the rectangle are l =4 and w = 96

Maximum area = 4(96) = 384

5 0
3 years ago
THROUGH (-1,-2) PARALLEL TO Y +7/6X+1
julia-pushkina [17]

Answer:

If a line is parallel to another line, the slopes of both lines are the same. So far the equation would be, y=7/6x+b. To find the value of b, you substitute the given point into the equation. -2=7/6(-1)+b, -2=-7/6+b, b=-5/6. So the equation of the line is y=7/6x-5/6.

:)

4 0
2 years ago
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