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hjlf
3 years ago
6

The formula to compute a person's body mass index is B = 700 x W/H2 (W/H2 means W/h squared, the h is squared)

Mathematics
1 answer:
RoseWind [281]3 years ago
3 0
By "solve" in part A, do you mean make W the subject of the formula? In which case:
A:  B = 700 x W/h2
     B x h2 =700 x W
     (B x h2)/700=W
B: (21.45 x 64^{2})/700=W
     87859.2/700=W
     126=W
     126 pounds
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aleksley [76]

Answer:

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Step-by-step explanation:

f(2) is asking for what the y value is when x is 2. f(4) is also asking what the y value is when x=4. When y=-2 the x is 8 and when the y=6 x=4. I hope this is helpful.

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3 years ago
X^2 -9X = 0. Factor and use the Zero property to solve
Veseljchak [2.6K]
The first step of factoring is to try to factor out a common factor.
The terms x^2 and -9x have the factor x in common.
Factor out x from both terms.

x^2 - 9x = 0

x(x - 9) = 0

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x = 0   or   x - 9 = 0

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5 0
3 years ago
What is the location of point C?<br><br><br><br> (-7, -2)<br> (-2, -7)<br> (-2, 7)<br> (-7, 2)
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x comes before Y

5 0
3 years ago
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Asher please $156 every six weeks for piano lessons what is the price per year for piano lessons
Svet_ta [14]
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3 years ago
Please help me!! 100 points!!
Lyrx [107]
Part A.

We could take, for example:

\begin{cases}x\geq-3\\y\geq3\end{cases}

For x ≥ -3 we have vertical line (x-intercept = -3) and shaded region on the right side of the line.
For y ≥ 3 we have horizontal line (y-intercept = 3) and shaded region above that line.

Part B.

Simply, substitute x and y coordinates of D and E <span>to the system of inequalities from part A, and check if its is true, what we get.
</span>
D=(-2,4)\\\\\begin{cases}x\geq-3\\y\geq3\end{cases}\quad\implies\quad\begin{cases}-2\geq-3\qquad\text{True}\\4\geq3\qquad\text{True}\end{cases}

so point D is a solution,

E=(2,4)\\\\\begin{cases}x\geq-3\\y\geq3\end{cases}\quad\implies\quad\begin{cases}2\geq-3\qquad\text{True}\\4\geq3\qquad\text{True}\end{cases}

and point E is also a solution to <span>our system of inequalities.
</span> 
Part C.

There are two ways we could do that. First is the same as in part B. We substitute x and y coordinates of each school and check if inequality is true or false:

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F=(3,-4)\\\\y\ \textless \ 3x-3\quad\implies\quad-4\ \textless \ 3\cdot3-3\quad\implies\quad-4\ \textless \ 6\quad\text{True}\\\\\\

So Timothy can attend schools C and F.

We can also draw a graph of that inequality (pic 2).

8 0
3 years ago
Read 2 more answers
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