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Genrish500 [490]
3 years ago
5

7/8 x c for c =8. How do I figure out the answer to this problem?

Mathematics
1 answer:
kobusy [5.1K]3 years ago
3 0
7/8 times 8
7/8 times 8/1
56 over 8
divide 56 by 8
the answer is 7.25 or 7 if you are rounding 
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How do I solve 20? Thanks
Gnom [1K]
20)

using
<span>a^3 + b^3 = (a+b)(a^2 − ab + b^2)
</span>so
w^3 + 125z^3
= w^3 +(5z)^3
= (w + 5z)(w^2 - 5wz + 25z^2)

hope it helps
6 0
4 years ago
All sides of quadrilateral ABCD are tangent to circle P.
VARVARA [1.3K]

Answer:

44.4 units

Step-by-step explanation:

Recall: 2 tangents drawn from an external point from a circle are congruent

Perimeter of the quadrilateral = AB + BC + CD + AD

AB = 3.1 + 8 = 11.1

BC = 3.1 + 8 = 11.1

CD = 11.1 (given)

AD = 8 + 3.1 = 11.1

Perimeter = 11.1 + 11.1 + 11.1 + 11.1

= 44.4 units

6 0
3 years ago
Find the circumference of the circle. Use π=3.14
Masteriza [31]
The circumference formula for a circle is 'c=2πr'.

C = circumference
π = 3.24
r = radius (1/2 the diameter)

All you need to do is plug in the numbers you are given. So the circumference = (2)(3.14)r
5 0
3 years ago
NBA Youngboy has 12 bullets in his clip he fires 4 and misses Kodak Black. What is NBA Youngboy left with?
Anika [276]

Hello there, to answer your question...

12-4=8

Therefore NBA is left with 8 bullets.

Lol I love the sense of humor in the question...

I hope this helps :)

4 0
3 years ago
Read 2 more answers
Karen is starting a career as a professional wildlife photographer and plans to photograph Canadian Geese at one of the staging
balandron [24]

Answer:

$5000*0.816 = $4082

Step-by-step explanation:

It's a strange question, but based on the statement and the question it sounds like it's a poisson distribution:

* For 3 days she was able to get 2 good shots (<em>typical of that time of the year</em>)

* Good shots happen randomly

* Each day is independent of another

Let's call 'p' the probability that she makes a good shot per day

Let's call 'n' the number of days Karen is taking shots.

So, if in 3 days he got 2 good shots and that is typical at that time of the year, then the expected value for the number of good shots (X) is:

E(x)=\frac{2}{3}

For a Poisson distribution E (x)=\lambda\\\lambda= np

So:

\lambda =\frac{2}{3}

For a Poisson distribution the standard deviation is:

\sigma = \sqrt{\lambda}\\\sigma = \sqrt{\frac{2}{3}}

\sigma = 0.816 this is the standard deviation for the number of buentas taken.

So the standard deviation for income is the price of each shot per sigma

$5000*0.816 = $4082, which is the desired response.

3 0
3 years ago
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