Step-by-step explanation:
as the graphic shows, there are 2 objects : 1 block and 1 triangular shaped half-block.
the block is
7cm × 6cm × 2cm
the half-block is
8cm × 7cm × 6cm
with 10cm being the length of the tilted "roof" area.
the 2 sides facing each other are not visible to the observer, so, they are not part of the surface area of the composite figure.
let's start with the block :
top and bottom 7×2
front and back 6×2
no left (fully covered by the half-block)
right 6×7
that gives us :
2 × 7×2 = 2×14 = 28 cm²
2 × 6×2 = 2×12 = 24 cm²
6×7 = 42 cm²
in total : 94 cm²
the half-block :
top 10×7
bottom 8×7
front and back (triangles) 8×6/2
no left (due to being a half-block)
no right (fully covered by the block)
that gives us :
10×7 = 70 cm²
8×7 = 56 cm²
2 × 8×6/2 = 2×24 = 48 cm²
in total : 174 cm²
so, the complete surface area of the composite figure is
94 + 174 = 268 cm²
The additive inverse of a number is what u add to that number to get 0.
The additive inverse of a = -a so the additive inverse of 16 5/7 = -16 5/7
Answer:
The third answer option is correct. sqrt(x) = x^(1/2). So sqrt(121) = 121^(1/2)
The total amount of hamburger that the manager of the store in the morning = 35.75 pounds
Quantity of hamburger sold to one customer during the day = 15.4 pounds
Quantity of hamburger sold to another customer during the day = 13.22 pounds
Total quantity of hamburger sold
by the manager during the day = (15.4 + 13.22) pounds
= 28.62 pounds
Then
The quantity of hamburger left in the store to sell = (35.75 - 28.62) pounds
= 7.13 pounds
So 7.13 pounds of hamburger is still left to be sold.
Answer:
The margin of error for a confidence interval for the population mean with a 90% confidence level is 0.53 hours.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
In this quesstion:
So
The margin of error for a confidence interval for the population mean with a 90% confidence level is 0.53 hours.
