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sukhopar [10]
3 years ago
5

Could someone answer this please NO LINKS AND REAL ANSWERS!!

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
4 0

Answer:

im doing the same thing were the same

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Show work, please someone help me, i'm confused still on this concept.
BigorU [14]
Answer: choice C) -15x^4y

-----------------------------------------

Explanation:

The coefficients are -3 and 5. They are the numbers to the left of the variable terms
Multiply the coefficients to get -3*5 = -15. So -15 is the coefficient in the answer

Multiply the x terms to get x^3 times x = x^(3+1) = x^4. Notice the exponents are being added

Do the same for the y terms as well: y^2 times y^(-1) = y^(2+(-1)) = y^(2-1) = y^1 = y

So we have a final coefficient of -15, the x terms simplify to x^4 and the y terms simplify to just y

Put this all together and we end up with -15x^4y which is what choice C is showing

3 0
3 years ago
Which numbers are the extremes of the proportion shown below?
wolverine [178]

Answer:

A 3 and 8

Step-by-step explanation:

if a/b=c/d, the extremes are "a" and "d". The means would then be "b" and "c"

8 0
2 years ago
Eight more than the product of two and a number x.
olchik [2.2K]
8+2x is the answer. The rest of these characters is for the >20 rule
5 0
3 years ago
Read 2 more answers
A piece of string is 1650 cm long.
balandron [24]

Answer: The smaller piece is 750m long.

Step-by-step explanation:

let the smaller piece be x

so

150m + x + x = 1650

150 + 2x = 1650

or, 2x = 1500

so, x = 750 m

4 0
3 years ago
Read 2 more answers
Given a focus of (4, 5) and directrix of y= -3 , find the equation of the parabola.
andrey2020 [161]
Check the picture below.

notice, the focus point is at 4,5 whilst the directrix line is at y = -3, below the focus point, meaning the parabola is vertical and opening upwards.

keeping in mind that the vertex is "p" distance from either of these fellows, then the vertex is half-way between both of them, notice in the picture, the distance from y = 5 to y = -3 is 8 units, half that is 4 units, thus the vertex 4 units from the focus or 4 units from the directrix, that puts it at (4,1), whilst "p" is 4, since the parabola is opening upwards, is a positive 4 then.

\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
(y-{{ k}})^2=4{{ p}}(x-{{ h}})
\\\\
\boxed{(x-{{ h}})^2=4{{ p}}(y-{{ k}})}
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\
-------------------------------

\bf \begin{cases}
h=4\\
k=1\\
p=4
\end{cases}\implies (x-4)^2=4(4)(y-1)\implies (x-4)^2=16(y-1)
\\\\\\
\cfrac{1}{16}(x-4)^2=y-1\implies \cfrac{1}{16}(x-4)^2+1=y

8 0
3 years ago
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