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vova2212 [387]
3 years ago
12

Multiply: 6√x * 4√y^3

Mathematics
2 answers:
ratelena [41]3 years ago
8 0

Answer: it's option b.

Step-by-step explanation:

EastWind [94]3 years ago
7 0

Answer:

The third answer option is correct.  sqrt(x) = x^(1/2).  So sqrt(121) = 121^(1/2)

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Instead of having 1.5 times as many pink flowers as white
elena55 [62]

Answer:

The first row has 4 pink flowers and 2 white flowers

The second row has 6 pink flowers and 3 white flowers

The third row has 8 pink flowers and 4 white flowers.

Step-by-step explanation:

Based on the above question,

Molly has decided to plant a garden with twice as

many pink flowers as white flowers per row.

We can find the number of white flowers in each row by using the principle of ratio to solve this question.

Mathematically, what Molly planted is expressed as:

2 pink flowers : 1 white flower

Therefore for the three rows:

a. The first row is 4 pink flowers

Since, 2 pink flowers : 1 white flower

2 pink flowers = 1 white flower

4 pink flowers = designated as y

We cross multiply

2× y = 4 × 1

Divide both sides by 2

y = 4 ÷ 2

y = 2 white flowers.

Therefore, the first row that Molly planted 4 pink flowers has 2 white flowers.

b. The second row, Molly planted 6 pink flowers

Since, 2 pink flowers : 1 white flower

2 pink flowers = 1 white flower

6 pink flowers = designated as z

We cross multiply

2× z = 6 × 1

Divide both sides by 2

z = 6 ÷ 2

z = 3 white flowers.

Therefore, the second row that Molly planted 6 pink flowers has 3 white flowers.

c. The third row , Molly planted 8 pink flowers

Since, 2 pink flowers : 1 white flower

2 pink flowers = 1 white flower

8 pink flowers = designated as p

We cross multiply

2× p = 4 × 1

Divide both sides by 2

P = 8 ÷ 2

y = 4 white flowers.

Therefore, the third row that Molly planted 8 pink flowers has 4 white flowers.

Therefore, since Molly has decided to plant a garden with twice as

many pink flowers as white flowers per row,

The first row has 4 pink flowers and 2 white flowers

The second row has 6 pink flowers and 3 white flowers

The third row has 8 pink flowers and 4 white flowers.

6 0
3 years ago
Read 2 more answers
How to solve a system of equations using elimination?
Nastasia [14]
If  you have a problem like: 
4x+2y=20
2x+2y=16
 You would subtract
4x-2y=20
-2x+2y=16
You would get the new problum
2x=4
You now want to divide the 2 on both sides to solve for x
x=2

Now that you've solved for X you want to solve for y. So use substitution to solve for y. You would want to substatute the x for the 2 in either of the problums. I'll use the first one.
4(2)+2y=20

You first want to multiply te 4(2) you would get a new problum.
8+2y=20

Now you want to subtract the 8 on both sides.
2y=12

The last step to solve for y is to divide the 2 on both sides.
Y=6

So your answers would be
x=2
y=6


5 0
3 years ago
What 3 numbers that you can X to get 120
Yuri [45]
3 numbers you can multiply to get 120:

1. 12
2. 6
3. 3

Hope this helps! :D

~PutarPotato
6 0
3 years ago
Read 2 more answers
1.A bag has 4 green blocks, 3 red blocks, 2 blue blocks, and 1 yellow block. Find the probability of randomly selecting a block
maks197457 [2]

Answer: 1) 7/10  2) 15  3) 240  4) 1/4  5) 4/9  6) 1/20  7) No, not independent

Step-by-step explanation:

1. 4 green+3red+2blue+1yellow = 10 total

if 3/10 are red, then 7/10 are not red. So the second option, 7/10

2. 3 cartons in every 40

40*5 = 200

so do 3*5 = 15

so 15 or the third option

3. 40 out of 110

110*6 = 660

so do 40*6 = 240

so 240 or the fourth option

4.

Flipping heads: 1/2

rolling even: well, there is 2, 4, and 6, or 3 even numbers so 3/6 or 1/2

do 1/2*1/2 = 1/4

so 1/4 or the third option

5. Numbers more than 2: 3, 4, 5, 6 (4 numbers)

4/6 or 2/3 chance the first time, 2/3 chance the second time

do 2/3*2/3 = 4/9

so 4/9 or the second option

6. 5 dishes and 4 desserts

1/5 chance of picking the dish

1/4 chance of picking the dessert

do 1/5*1/4 = 1/20

so 1/20 or the fourth option

7. Since you don’t replace the marble after picking it, it affects the outcome of the second draw. Therefore the events are dependent, or not independent. So the second option.

7 0
3 years ago
Algebra 2 semester 2 activity 4.1.1
podryga [215]
I don’t know what your asking
8 0
3 years ago
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