Answer:
Following are the statement:
counterPointer = &counter;
Explanation:
The following statement is correct because in the question it is given that there is an integer data type variable i.e., "counter" and there is another integer data type pointer variable i.e., "counterPointer" and finally we write a statement in which the pointer variable points to the integer variable.
Here you go plz mark brainlist
Answer:
having a capital and lower case letters and a special characters and numbers.
Explanation:
it should be hard but easy enough to remember and no one will know
Answer:
"ArithmeticException" is the correct answer for the above question.
Explanation:
Missing Information : The above question does not hold that "what is the output of the program".
- The above question has a class that holds the two functions one function is the main function which calls the other function in a try-catch block.
- The method function holds one run time exception which is 1/0 which is an arithmetic exception.
- It can be handle by the help of an arithmetic class object which is defined in the first catch block.
- Hence the print function of this catch is executed and prints "ArithmeticException".
The correct answer is A it transfers control to the next loop in the program.
The most valid answer is that the break statement Exits the loop and continues executing the program, but assuming that there are other loops, the control of the program will go to them since the first loop is broken out of.
