Solution:
initial = float(eval(input('Enter the monthly saving amount: ')))
x = (1 + 0.00417)
month_one = initial * x
month_two = (initial + month_one) * x
month_three = (initial + month_two) * x
month_four = (initial + month_three) * x
month_five = (initial + month_four) * x
month_six = (initial + month_five) * x
print('The sixth month value is: '+str(month_six))
Don't forget the saving amount, and initialize the balance with that amount. Inside the loop, work out and add the interest and then add the saving amount for the next month.
balance = 801
for month in range(6):
balance = balance * (1.00417)
print(balance)
Answer: Crossover
Explanation:
Based on the information given in the question, the type of cable that should be used is the crossover cable.
Crossover cable is used for a direct connection of computing devices. A crossover cable is typically used for the connection of computing devices that are of identical types.
Since the LAN port on a router is to be connected to the uplink port on a switch and the switch does not support auto-MDI, the crossover cable can be used.
A mixture can be composed of a few individual objects or several complex groups of objects.
Hope I helped! ( Smiles )
Answer:
Induced current is 0.226 A
Explanation:
To calculate potential difference we have

putting values we get
the p.d is 141.3
Answer:
All functions were written in python
addUpSquaresAndCubes Function
def addUpSquaresAndCubes(N):
squares = 0
cubes = 0
for i in range(1, N+1):
squares = squares + i**2
cubes = cubes + i**3
return(squares, cubes)
sumOfSquares Function
def sumOfSquares(N):
squares = 0
for i in range(1, N+1):
squares = squares + i**2
return squares
sumOfCubes Function
def sumOfCubes(N):
cubes = 0
for i in range(1, N+1):
cubes = cubes + i**3
return cubes
Explanation:
Explaining the addUpSquaresAndCubes Function
This line defines the function
def addUpSquaresAndCubes(N):
The next two lines initializes squares and cubes to 0
squares = 0
cubes = 0
The following iteration adds up the squares and cubes from 1 to user input
for i in range(1, N+1):
squares = squares + i**2
cubes = cubes + i**3
This line returns the calculated squares and cubes
return(squares, cubes)
<em>The functions sumOfSquares and sumOfCubes are extract of the addUpSquaresAndCubes.</em>
<em>Hence, the same explanation (above) applies to both functions</em>