Please help me asap!!! Im stuck.

Question 6(Multiple Choice Worth 1 points)

Vaselesa [24]

Using translation concepts, the correct option is given as follows:

The graph of f(x) is shifted to the right to create g(x).

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s definition or in it’s domain. Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis.

For this problem, the functions are given as follows:

f(x) = |x|.

g(x) = |x - 31|.

That is, g(x) = f(x - 31), hence the function was shifted 31 units to the right and the correct option is given by:

The graph of f(x) is shifted to the right to create g(x).

More can be learned about translation concepts at brainly.com/question/4521517

#SPJ1

7 0

2 years ago

Find the mode and median of the data. A. mode = 41 median = 72 B. mode = 72 median = 94 C. mode = 94 median = 94 D. mode = 94 me

SashulF [63]

Mode means the number that apperss the most
median is the number in the middle when you arrange them in numerical order

ok so
you take the unbers fom the left most collumn and pair it with each number in the right side of the line, the left collumn is the tens place and the right hand side is the ones

so the th enumbers are

32,41,41,50,56,57,62,70,70,72,72,72,73,74,91,92,94,94,94,94

mode=most common number
94 appears 4 times which is most
mode=94

median is number in very middle number
20 terms
72 is in middle

mode=94
72=median

D is answer

7 0

3 years ago

Read 2 more answers

Jack has some marbles. He has ten more red marbles than blue marbles. He has fewer yellow marbles than blue marbles.

kap26 [50]

Answer:

Jack has at least 15 marbles: 12 red, 2 blue and 1 yellow.

Step-by-step explanation:

1. Let's review the information given to us to solve the problem correctly:

Number of red marbles = 10 more than blue marbles

Number of yellow marbles fewer than blue marbles

2. How many of each color marble could Jack have?

r = Number of red marbles

b = Number of blue marbles

y = Number of yellow marbles

r = b + 10

y < b

If y = 1, then b ≥ 2, and r = b + 10,

fulfilling the three conditions, we have:

y = 1, b = 2, and r = 12

5 0

3 years ago

"Immediately after a ban on using hand-held cell phones while driving was implemented, compliance with the law was measured. A r

sergiy2304 [10]

Answer:

(a) Null Hypothesis, $H_0$ : $p_1-p_2=0$ or $p_1= p_2$

Alternate Hypothesis, $H_A$ : $p_1-p_2\neq 0$ or $p_1\neq p_2$

(b) We conclude that there is a statistical difference in these two proportions measured initially and then one year later.

Step-by-step explanation:

We are given that a random sample of 1,250 drivers found that 98.9% were in compliance. A year after the implementation, compliance was again measured to see if compliance was the same (or not) as previously measured.

A different random sample of 1,100 drivers found 96.9% compliance."

Let $p_1$ = proportion of drivers that were in compliance initially

$p_2$ = proportion of drivers that were in compliance one year later

(a) Null Hypothesis, $H_0$ : $p_1-p_2=0$ or $p_1= p_2$ {means that there is not any statistical difference in these two proportions measured initially and then one year later}

Alternate Hypothesis, $H_A$ : $p_1-p_2\neq 0$ or $p_1\neq p_2$ {means that there is a statistical difference in these two proportions measured initially and then one year later}

The test statistics that will be used here is Two-sample z proportion statistics;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{ \frac{\hat p_1(1-\hat p_1)}{n_1} + \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of drivers in compliance initially = 98.9%

$\hat p_2$ = sample proportion of drivers in compliance one year later = 96.9%

$n_1$ = sample of drivers initially = 1,250

$n_2$ = sample of drivers one year later = 1,100

(b) So, the test statistics = $\frac{(0.989-0.969)-(0)}{\sqrt{ \frac{0.989(1-0.989)}{1,250} + \frac{0.969(1-0.969)}{1,100}} }$

= 3.33

Now, P-value of the test statistics is given by;

P-value = P(Z > 3.33) = 1 - P(Z $\leq$ 3.33)

= 1 - 0.99957 = 0.00043

Since in the question we are not given with the level of significance so we assume it to be 5%. Now at 5% significance level, the z table gives critical values between -1.96 and 1.96 for two-tailed test.

Since our test statistics does not lies within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that there is a statistical difference in these two proportions measured initially and then one year later.

7 0

3 years ago

4 1/9 - 3 3/5 what is the answer to this question ?

Sindrei [870]

The answer is 0.51111111111111111 (It goes on for infinity).

8 0

3 years ago