We can write and solve the differential equation that fits the statement given;
dy/dt = k(50-t)
∫dy = ∫ k(50-t)dt
= ∫ (50k - kt) dt
therefore;
y = 50kt - k/2(t²) + C
Alternatively, can be written as
y = - k/2 (50-t)² + C)
Answer:
8
Step-by-step explanation:
2x - 5 > 3 or -4x + 7 < -25
2x < 8. or -4x < -32
x < 4. or. x > 8
|4-9|
|-5|
5
|4|-9
4-9
-5
absolute value is the numbers distance from zero
<span>Your football team gained 4 yards on first down and 2 yards on second down during its last possession. Which number is the additive inverse of the yards gained?</span>
1. 7/20
2. 3/10
3. 11/20
4. 21/25
5. 59/100
6. 6 39/100
9. 3 17/50
11. 0.008
