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2 years ago

Determine the largest integer value of x in the solution of the following inequality.

Mathematics

1 answer:

steposvetlana [31]2 years ago

7 0

Answer:

x=2

Step-by-step explanation:

-5(2)+6= -4

-4 is greater than -5

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Write a number in which value of the digit 3 is 10 times as much as the value of the digit 3 in 942381 show your thinking.

choli [55]

Answer:

943,281

Step-by-step explanation:

Just move the 3 up a value

If it's in the ten's place, then move it to the hundred's place value.

If it's in the hundred's place, then move it to thousand's place value.

So on and so on...

8 0

4 years ago

Read 2 more answers

If i just completed my daily Mindkeeper five-kilometer training run, how many meters did I run

galina1969 [7]

Answer:

5000

Step-by-step explanation:

5 0

3 years ago

The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t

shtirl [24]

Answer:

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

Step-by-step explanation:

As the given Augmented matrix is

$\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 1 :

$r_{1}$ ↔ $r_{1} - r_{2}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 2 :

$r_{3}$ ↔ $r_{3} - 8r_{1}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]$

Step 3 :

$r_{2}$ ↔ $\frac{r_{2}}{7}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]$

Step 4 :

$r_{1}$ ↔ $r_{1} + 14r_{2}$ , $r_{3}$ ↔ $r_{3} - 124r_{2}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]$

Step 5 :

$r_{3}$ ↔ $\frac{r_{3}. 7}{254}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]$

Step 6 :

$r_{1}$ ↔ $r_{1} - 4r_{3}$ , $r_{2}$ ↔ $r_{2} + \frac{1}{7} r_{3}$

$\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]$

∴ we get

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

6 0

3 years ago

Which of the following proportions is false? 10/25 = 40/100 24/30 = 20/25 18/48 = 20/50 25/45 = 75/135

Liono4ka [1.6K]

Answer:

18/48=20/50 is wrong

Step-by-step explanation:

Because 18/48=37.5% and 20/50=40%

Hope it helps

3 0

2 years ago

there are 3 black marbles in and 4 red marbles in a bag. what is the probability that you will pick two black marbles put of the

professor190 [17]

$|\Omega|=7\cdot6=42\\ |A|=3\cdot2=6\\\\ P(A)=\dfrac{6}{42}=\dfrac{1}{7}\approx14\%$

5 0

3 years ago