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Vitek1552 [10]
4 years ago
7

Biologists have proposed a cubic polynomial to model the length l of alaskan rockfish at age a:l = 0.0155a3 − 0.372a2 + 3.95a +

1.21, where l is measured in inches and a is in years. (a) (2 pts) calculate dl da a=12 (b) (2 pts) interpret your answer.
Mathematics
1 answer:
Kryger [21]4 years ago
3 0
(a) To answer this item, we are to differentiate the given equation, l, in terms of a. This is as shown below.

            dl/da = 3(0.0155)a² - 2(0.372)a + 3.95

Substituting the known value, a = 12
          dl/da = (3)(0.0155)(12)² - 2(0.372)(12) + 3.95

Simplify,
       dl/da = 1.718

(b) The answer in a tells us that the length of the alaskan rockfish will change at a rate of 1.718 inches/year when it is already 12 years old. 
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Simplify the coefficient of z on the left side. We do this by rationalizing the denominators and multiplying them by their complex conjugates:

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\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{3 - 5i + 2(-1)}2 - \dfrac{5 - 7i - 6(-1)}5

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\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{1 - 5i}2\cdot\dfrac55 - \dfrac{11 - 7i}5\cdot\dfrac22

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So, the equation is simplified to

-\dfrac{17+11i}{10} z = \dfrac12 - \dfrac{2i}5

Let's combine the fractions on the right side:

\dfrac12 - \dfrac{2i}5 = \dfrac12\cdot\dfrac55 - \dfrac{2i}5\cdot\dfrac22

\dfrac12 - \dfrac{2i}5 = \dfrac{5-4i}{10}

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-\dfrac{17+11i}{10} z = \dfrac{5-4i}{10}

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Multiply both sides by -1/(17 + 11i) :

\dfrac{-(17+11i)}{-(17+11i)} z = \dfrac{5-4i}{-(17+11i)}

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-\dfrac{5-4i}{17+11i} = -\dfrac{5-4i}{17+11i} \cdot \dfrac{17-11i}{17-11i}

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