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2 years ago

Find the product (7m^2-3m-7)(m^2-7m-6)

Mathematics

1 answer:

earnstyle [38]2 years ago

4 0

Answer:

7m^4-52m^3-28m^2+67m+42

Step-by-step explanation:

(7m^2-3m-7)(m^2-7m-6)

7m^4-3m^3-7m^2-49m^3+21m^2+49m-42m^2+18m+42

7m^4-3m^3-49m^3-7m^2+21m^2-42m^2+49m+18m+42

7m^4-52m^3-28m^2+67m+42

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<h3>Further explanation</h3>

<u>Given: </u>

The total weight of 6 pieces of butter and a bag of sugar is 3.8 Ib.
The weight of the bag of sugar is 1.4 Ib

<u>Question: </u>

What is the weight of each piece of butter?

<u>The Process: </u>

The two steps for obtaining the weight of each piece of butter are as follows:

<u>Step-1:</u> the total amount of butter is the total bag of butter and sugar subtracted by the weight of the bag of sugar.

$\boxed{ \ 3.8 \ lbs - 1.4 \ lbs = 2.4 \ lbs \ }$

<u>Step-2:</u> the total amount of butter divided by the number of pieces of butter is the the weight of each piece of butter.

$\boxed{ \ 2.4 \ lbs \div 6 \ pieces = \boxed{ \ 0.4 \ lbs/piece \ } \ }$

Let's also consider the following quick steps.

<u>Quick steps: </u>

$\boxed{ \ \frac{(3.8 - 1.4) \ lbs}{6 \ pieces} = \boxed{ \ 0.4 \ lbs/piece \ } \ }$

Therefore, the weight of each piece of butter is 0.4 lbs.

<h3>Learn more </h3>

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Find the product (7m^2-3m-7)(m^2-7m-6)​

Find the product (7m^2-3m-7)(m^2-7m-6)