Question

The equation of a circle whose center is at (4, 0) and radius is length 2√(3) is

Answer 1

ANSWER

${(x - 4)}^{2} + {y}^{2} = 12$

EXPLANATION

The equation of a circle given the center (h,k) and radius r is given by:

${(x - h)}^{2} + {(y - k)}^{2} = {r}^{2}$

The circle has center (4,0) and radius

$r = 2 \sqrt{3}$

We substitute the center and radius to get,

${(x - 4)}^{2} + {(y - 0)}^{2} = {(2 \sqrt{3)} }^{2}$

${(x - 4)}^{2} + {(y - 0)}^{2} = 12$

${(x - 4)}^{2} + {y}^{2} = 12$