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ladessa [460]
3 years ago
10

The equation of a circle whose center is at (4, 0) and radius is length 2√(3) is

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
3 0

ANSWER

{(x - 4)}^{2}  +  {y}^{2}  = 12

EXPLANATION

The equation of a circle given the center (h,k) and radius r is given by:

{(x - h)}^{2}  +  {(y - k)}^{2}  =  {r}^{2}

The circle has center (4,0) and radius

r = 2 \sqrt{3}

We substitute the center and radius to get,

{(x - 4)}^{2}  +  {(y - 0)}^{2}  =  {(2 \sqrt{3)} }^{2}

{(x - 4)}^{2}  +  {(y - 0)}^{2}  = 12

{(x - 4)}^{2}  +  {y}^{2}  = 12

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