(Algebra 1 ~ High School)
2 answers:
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Answer:
The quantity of cement use is 125 pounds
The quantity of sand use is 375 pounds
The quantity of gravel use is 500 pounds
Step-by-step explanation:
Given as :
The ratio of cement to sand to gravel = 1 : 3 : 4
The total quantity of dry mix required = 1000 pounds
Let The quantity of cement required = 1 × x pounds
The quantity of sand required = 3 × x pounds
The quantity of gravel required = 4 × x pounds
So, According to question
The total quantity of dry mix required = The quantity of cement required + The quantity of sand required + The quantity of gravel required
Or, x + 3 x + 4 x = 1000 pounds
Or, 8 x = 1000 pounds
∴ x =
I.e x = 125
So , The quantity of cement required = 1 × 125 pounds = 125 pounds
The quantity of sand required = 3 × 125 pounds = 375 pounds
The quantity of gravel required = 4 × 125 pounds = 500 pounds
Hence The quantity of cement use is 125 pounds
The quantity of sand use is 375 pounds
The quantity of gravel use is 500 pounds
Answer
Answer:
(I)Sin Θ=4/5
(II) Cos Θ =-3/5
(III) Tan Θ = -4/3
(IV) Cosec Θ = 5/4
(V) Sec Θ = -5/3
(VI) Cot Θ = -3/4
Step-by-step explanation:
(-24,18)
This lies in the second quadrant from the diagram.
Note that the angle is at the origin (0,0).
Using Pythagoras triples(18,24,30)
Hypotenuse = 30
Opposite=-24
Adjacent=18
(I)Sin Θ= Opposite/Hypotenuse
=-24/30=-4/5
Note: (Sine is Positive in the Second Quadrant)
Sin Θ =4/5
(II) Cos Θ = Adjacent/Hypotenuse
=18/30=3/5
Since Cosine is negative in the Second Quadrant
Cos Θ=-3/5
(III) Tan Θ = Opposite/Adjacent
Tan Θ = -24/18= -4/3
(IV) Cosec Θ = 1/Sin Θ = 5/4
(V) Sec Θ = 1/cos Θ = -5/4
(VI) Cot Θ = 1/tan Θ = -3/4
