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masha68 [24]
3 years ago
5

A motel rents double rooms at $34 per day and single rooms at $26 per day. If 26 rooms were rented one day for a total of $804,

how many rooms of each kind were rented?
Mathematics
1 answer:
lubasha [3.4K]3 years ago
5 0

Answer: 16 double rooms and 10 single rooms were rented.

Step-by-step explanation:

Let x represent the number of double rooms that were rented.

Let y represent the number of single rooms that were rented.

The total number of rooms rented in a day is 26. It means that

x + y = 26

A motel rents double rooms at $34 per day and single rooms at $26 per day. If all the rooms that were rented for one day cost a total of $804, it means that

34x + 26y = 804 - - - - - - - - - - -1

Substituting x = 26 - y into equation 1, it becomes

34(26 - y) + 26y = 804

884 - 34y + 26y = 804

- 34y + 26y = 804 - 884

- 8y = - 80

y = - 80/ - 8 = 10

x = 26 - y = 26 - 10

x = 16

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