Answer:
Question 1
Total number of marbles = 5 + 7 + 8 = 20
(a)
- P(red, red) = 5/20*4/19 = 1/19
(b)
- P(white, blue or blue, white) = 7/20*8/19 + 8/20*7/19 = 14/95 + 14/95 = 28/95
(c)
- P(both same colour) = P(red,red or blue,blue or white,white) =
- 1/19 + 8/20*7/19 + 7/20*6/19 = (20 + 56 + 42)/380 = 118/380 = 59/190
Question 2
(a)
- P(A and B) = 2/9 * 4/11 = 8/99
(b)
- P(not A and not B) = (1 - P(A))(1 - P(B)) = 7/9*7/11 = 49/99
(c)
- P(A or B) = 1 - P(not A and not B) = 1 - 49/99 = 50/99
Value of the coin times number of coins summed up equal total value
so since we have "$2.10 in all"...
0.05n + 0.25q = 2.10
and we are told that there are "four times as many quarters as nickels"
this translates to
q = 4n
0.05n + 0.25q = 2.10
and
q = 4n
are your two equations that could be used to solve this problem
if you would like to know how many nickels and how many quarters there are, plug in q = 4n into the first equation and get
0.05n + 0.25(4n) = 2.10
multiply
0.05n + 1n = 2.10
add like terms
1.05n = 2.10
divide both sides by 1.05
n = 2.10/1.05 = 2
then plug that back into
q = 4n
so
q = 4(2) = 8
therefore you have
2 nickels
and
8 quarters
Given 2 points compute the slope m. then write a point slope form
y-y1=m(x-x1). solve this for y
y=mx - mx1 +y1
Answer:
i have no idea what to do but you can go to khan academy and search up how to solve these kind of questions
Step-by-step explanation:
7. 10 times negative 1 is -10
4.5 times -10 is 4.50