<span>Differentiation of </span><span>Cos(inv) {(a+bcosx)/(b+acosx)} =</span><span> -(((a + b Cos[x])/(Sqrt[1 - x^2] (b + ArcCos[x])^2) - (b Sin[x])/(b + ArcCos[x]))/Sqrt[1 - (a + b Cos[x])^2/(b + ArcCos[x])^2])</span>
Answer:
1:50 P.M
Step-by-step explanation:
12:15+35 = 12:50
1 hour = 60 minutes
60 + 12:50 = 1:50
